105/2^9
Step-by-step explanation:
The probability of getting a head in a single toss
p=12
The probability of not getting a head in a single toss
q=1−12=12
Now, using Binomial theorem of probability,
The probability of getting exactly r=4 heads in total n=10 tosses
=10C4(1/2)4(1/2)10−4
=10×9×8×7/4! 1/2^4 1/2^6
=2^44⋅9⋅35/24(2^10)
=105/2^9
The three ways are substitution, elimination, and graphing
V=(4/3)pir^2
c=2pir
12=2pir
divide 2
6=pir
divide by pi
6/pi=r
sub for r
V=(4/3)pi(6/pi)^2
V=(4/3)pi(36/(pi^2))
V=(4/3)(36/pi)
V=144/(3pi)
V=48/pi
aprox pi=3.141592
V=15.2788777155
V=15.28 in^3
X = adults
Y = child
X+y=168
X=168-y
$10x + $7y = $1446
10(168-y) + 7y = 1446
1680 - 10y + 7y = 1446
-3 y = -234
Y = 78
X = 168-78
X = 90
$10*90 + $7*78 =
$900 + $546 = $1446
