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3 years ago

12

I need help please and thank you

2 answers:

Flura [38]3 years ago

8 0

Answer:

30.5

Step-by-step explanation:

The dimensions of figure EFGH are one half those of figure ABCD, thus

FG = 6 and GH = 6, thus

perimeter = 12.5 + 6 + 6 + 6 = 30.5

daser333 [38]3 years ago

7 0

37 is the answer of this. Hope this helps :)

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Use the expression 14X + 28Y + 21.. what is the greatest common factor

12345 [234]

Answer:

1

Step-by-step explanation:

None of these numbers are alike terms so the only number left is 1.

4 0

3 years ago

Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?

Flura [38]

Answer:

The value to the given expression is 8

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3$

To find the value of the given expression:

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}$

( By using the property ( $(\frac{a}{b})^m=\frac{a^m}{b^m}$ )

$=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}$

( By using the property $(ab)^m=a^mb^m$ )

$=\frac{(10^{12})(5^6)}{(10^9)(5^9)}$

( By using the property $(a^m)^n=a^{mn}$ )

$=(10^{12})(5^6)(10^{-9})(5^{-9})$

( By using the property $\frac{1}{a^m}=a^{-m}$ )

$=(10^{12-9})(5^{6-9})$ (By using the property $a^m.b^n=a^{m+n}$ )

$=(10^3)(5^{-3})$

$=\frac{10^3}{5^3}$ ( By using the property $a^{-m}=\frac{1}{a^m}$ )

$=\frac{1000}{125}$

$=8$

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Therefore the value to the given expression is 8

3 0

3 years ago

Read 2 more answers

Tom has a fair spinner with six sides.

77julia77 [94]

Answer:

likely ❤️❤️❤️❤️❤️❤️❤️

3 0

3 years ago

If you save three pennies on January 1, six pennies on January 2, nine pennies on January 3, and continue this pattern for one y

lbvjy [14]

This is an arithmetic series with first term a1 = 3 and common difference = 3

Sum after 365 days = (365/2)[ 2*3 + (365-1)*3]

= 200,385 pennies = $2003.85 Answer

5 0

3 years ago

Solve the following equation for the variable indicated<br> 15 = Зn + 6р, for n

Taya2010 [7]

Answer:

Solving the equation $15 = 3n + 6p$ for variable n we get $\mathbf{n=5-2p}$

Step-by-step explanation:

We need to solve the equation $15 = 3n + 6p$ for variable n

Solving:

$15 = 3n + 6p$

Subtract both sides by 6p

$15-6p = 3n +6p -6p\\15-6p=3n$

Switch sides of equality

$3n=15-6p$

Divide both sides by 3

$\frac{3n}{3} =\frac{15-6p}{3}\\n=\frac{3(5-2p)}{3}\\n=5-2p$

So, solving the equation $15 = 3n + 6p$ for variable n we get $\mathbf{n=5-2p}$

8 0

3 years ago