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2 years ago

Maddison wants to buy a guitar she starts saving $35 each month witch equation represents maddisons savings (s) after n months

Mathematics

1 answer:

Verizon [17]2 years ago

6 0

Answer:

s=$35n

Step-by-step explanation:

have fun w/ this (also can I get brainiest?)

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The cost of a car, in dollars, t years after its purchase is $20,000 - $3,000t. Which statement is correct? please explain too.

xeze [42]

We start with 20,000. Every year t, we decrease 3,000. Thus, each year the car depreciates by 3,000 every year.

B

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3 years ago

What is the answer to this question<br> 2 1/2-d=1 3/4

goldenfox [79]

Answer:

d = 3/4

Step-by-step explanation:

2.5 - d = 1.75

-2.5 -2.5

------------------

-d = -0.75

d = 0.75

d = 3/4

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2 years ago

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Ivahew [28]

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3 years ago

Read 2 more answers

The opposite of -10 is. A. -(-(-10)). B. -10. C. 10. D. -|10| <br><br> Is the answer C.

Sedbober [7]

Hi!

I would believe the answer is C. Seems the most practical.

So yeah, C!

Hope this helps!

<h2><em>~~PicklePoppers~~</em></h2>

3 0

2 years ago

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

fenix001 [56]

Answer:

Step-by-step explanation:

Given that

$\alpha =2.5$ , $\beta =220$

The weibull distribution with parameters $\alpha \ \ and \ \ \beta$

where $\alpha =0 \ \ , \beta =0$

$F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha &x\geq 0\\0&x$

Then,

$F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x$

A) The probability that a specimen's lifetime is at most 250 is

$P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564$

The probability that the specimen's life time is more than 300 is

$P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}$

$=e^-^{(300/220)^{2.7}$

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

$P(100$

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

$P(X>x)=0.50\\\\1-P(X$

x = 192.07

7 0

2 years ago