You don't need 3 equations to get a general solution. To do this use the equations x-3y-z=0 and -x+2y+0z= -3. Start out by letting z = t. Then solving those 2 equations simultaneously, your x's cancel out leaving you with -y-z=-3. But since z=t, then -y=-3+t or y=3-t. Now sub that in for y in the first equation, along with the fact that z=t to get x-3(3-t)-t = 0 and solve for x. x=9-2t. So a general solution for this would be (9-2t, 3-t, t)
So, you have $15 in total to spend.
1. Subtract your admission fee. 15-5=10
2. Divide 10 by .85 to get the number of games you were able to play. 10 divided by .85 = 11.76
3. Now, since it says the minimum you were able to play, round to the nearest digit. 11.76=11
You were able to play a minimum of 1 game and a maximum of 11 games.
Answer:
5.5
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
We have to get the value of the expression of - ∛(- 8).
Now, we can write the expression as
- ∛(- 8)
=![-\sqrt[3]{-8}](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B-8%7D)
= 
{Converting into exponent form}
= ![-[(-2)^{3} ]^{\frac{1 }{3} }](https://tex.z-dn.net/?f=-%5B%28-2%29%5E%7B3%7D%20%5D%5E%7B%5Cfrac%7B1%20%7D%7B3%7D%20%7D)
{Since (- 2) × (- 2) × (- 2) = - 8}
= ![- [(-2)^{3\times \frac{1}{3} } ]](https://tex.z-dn.net/?f=-%20%5B%28-2%29%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%5D)
{Since we know that ![[x^{a}] ^{b} = x^{ab}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5D%20%5E%7Bb%7D%20%3D%20x%5E%7Bab%7D)
}
= - [- 2]
= 2 (Answer)
Answer:
C
Step-by-step explanation:
There is not enough information
