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Serhud [2]
3 years ago
10

If a varies directly as p, and a = 260 when p = 13, what is the value of a when p = 17?

Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

340

Step-by-step explanation:

As 260/13 = a/p

So, a/p = 20

Therefore, a= 20p

p=17

So, a = 20p

a= 20x17

a= 340

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suppose the divisor and the dividend of a division problem are both fractions between 0 and 1, and the divisor is greater than t
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Divisor and Dividend are fractions lying between 0 and 1

Also, Divisor > Dividend

⇒ A smaller number is being divided by a larger number

Whenever a smaller number is divided by a larger number, the quotient is less than 1

E.g. Let divisor be \frac{4}{5} and dividend be \frac{2}{5}

\frac{4}{5} ÷ \frac{4}{5} = \frac{1}{2}, which is less than 1

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7 0
3 years ago
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Mr. Salvi makes car payments of $489.95 each month.
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Answer:

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Step-by-step explanation:

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therefore, the expense= 489.95×12

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3 years ago
g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

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Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

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