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Serhud [2]
3 years ago
10

If a varies directly as p, and a = 260 when p = 13, what is the value of a when p = 17?

Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

340

Step-by-step explanation:

As 260/13 = a/p

So, a/p = 20

Therefore, a= 20p

p=17

So, a = 20p

a= 20x17

a= 340

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Answer:

= \sqrt{52} units

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D = \sqrt{(x₂ - x₁)² + (y₂ - y₁)²}

   =\sqrt{(6 - 2)² + (-1 -5)²}

   =\sqrt{4² + (-6)²}

   = \sqrt{16 + 36}

D = \sqrt{52} units

7 0
3 years ago
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Find the measure of angle X in the figure below
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What is the solution to the equation below? riund your answer to two decimal places. (24) log(3x) = 60
Amanda [17]

The answer is:  " x = 105.41 " . 

_____________________________________________

Explanation:

_____________________________________________

Given:   " 24 log (3x) = 60 " ;  Solve for "x" .

The default is to assume "base 10" for the "logarithm". 

_____________________________________________

Start by dividing each side of the equation by "24" ; 

       →   [ 24 log(3x) ] / 24  = 60 / 24 ; 

to get:  

_____________________________________________

 log (3x)  = 2.5 ;

_____________________________________________

Rewrite as:  log₁₀ (3x) = 2.5 ;  

_____________________________________________

Using the property of logarithms:

⇔    10⁽²·⁵⁾  =   3x  ;  

↔   3x = 10⁽²·⁵⁾   ;

         →  10^ (2.5) = 316.2277660168379332 ;

     →  3x = 316.227766016837933 ;  

Divide each side of the equation by "3" ;

  to isolate "x" on one side of the equation;

      and to solve for "x" ;

    →  3x / 3 =  316.2277660168379332 / 3  ;

to get:

    →   x = 105.4092553389459777333 ;

    →  round to 2 (two) decimal places;

_____________________________________________

         →   " x = 105.41 " .

_____________________________________________

 Hope this helps!

    Best wishes to you!

_____________________________________________

8 0
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What does the graph of an equation reveal about the solutions to the equation?
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It reveals whether the answers will be negative, and how many solutions the equation will have. 
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