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Serhud [2]
3 years ago
10

If a varies directly as p, and a = 260 when p = 13, what is the value of a when p = 17?

Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

340

Step-by-step explanation:

As 260/13 = a/p

So, a/p = 20

Therefore, a= 20p

p=17

So, a = 20p

a= 20x17

a= 340

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~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

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so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

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