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ryzh [129]
3 years ago
6

students at a bake sale sell bags of cookies for $2.25 each and bags of miniture muffins for $1.50 each. They received a $25 don

ation. the amount of money made from selling c bags of cookies and m bags of muffins can be modeled by the expression 2.25c + 1.5m +25. Interpret the expression 2.25c + 1.5m in this context.
Mathematics
2 answers:
svetoff [14.1K]3 years ago
4 0

Answer:

The students at a bake sale sell bags of cookies for $2.25 each and bags of miniature muffins for $1.50 each.

Now, c number of cookies bags can be represented by 2.25c.

And m number of miniature muffin bags can be represented by 1.50m.

They received a $25 donation.

Hence, the equation representing total money earned is :

2.25c+1.50m+25

Here 2.25c means c bags at $2.25 per bag and 1.50m means m bags for $1.50 each.

Soloha48 [4]3 years ago
3 0
2.25c+1.5m context is that 2.25c represents the price of selling bags of cookies, hint the c. 1.5m represents the price of selling muffins, hint the m. In whole the equation represent the amount of money the bake sale would make minus the $25 donation.

Please vote my answer brainliest. thanks!
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1) \frac{4}{6}+\frac{1}{8}=\frac{19}{24}

2) \frac{2}{6}+\frac{7}{8}=\frac{29}{24}

3) \frac{5}{6}-\frac{3}{8}=\frac{11}{24}

4) \frac{4}{6}+\frac{3}{8}=\frac{25}{24}

5) \frac{7}{8}-\frac{5}{6}=\frac{1}{24}

6) \frac{1}{6}+\frac{7}{8}=\frac{25}{24}

Step-by-step explanation:

In order to calculate the sum of two fractions, we first have to find the lowest common denominator of the two fractions, then multiply the numerator of each fraction by the ratio between the lowest common denominator and the original denominator, and then add/subtract the two new numerators.

1)

\frac{4}{6}+\frac{1}{8}=

Here the lowest common denominator between 6 and 8 is 24,

So we have to rewrite each fraction as having denominator 24: this means that we have to multiply both numerator and denominator of the 1st fraction by 4 (because 24/6=4), and both numerator and denominator of the 2nd fraction by 3 (because 24/8=3).

So the new numerators of the two fractions are:

4\cdot 4 = 16\\1\cdot 3 = 3

The expression then becomes:

\frac{4}{6}+\frac{1}{8}=\frac{16}{24}+\frac{3}{24}=\frac{16+3}{24}=\frac{19}{24}

2)

\frac{2}{6}+\frac{7}{8}=

Here the lowest common denominator between 6 and 8 is again 24,

so we have again to multiply both numerator and denominator of the 1st fraction by 4, and both numerator and denominator of the 2nd fraction by 3.  

So the new numerators of the two fractions are:

2\cdot 4 = 8\\7\cdot 3 = 21

And we get:

\frac{2}{6}+\frac{7}{8}=\frac{8}{24}+\frac{21}{24}=\frac{8+21}{24}=\frac{29}{24}

3)

\frac{5}{6}-\frac{3}{8}

The denominators are the same, so the lowest common denominator is always 24. So we can adopt the same procedure, and new numerators are:

5\cdot 4 = 20\\3\cdot 3 = 9

And so:

\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{20-9}{24}=\frac{11}{24}

4)

\frac{4}{6}+\frac{3}{8}=

Using the same lowest common denominator, 24, the new numerators are:

4\cdot 4 = 16\\3\cdot 3 = 9

And so we can rewrite the expression as

\frac{4}{6}+\frac{3}{8}=\frac{16}{24}+\frac{9}{24}=\frac{16+9}{24}=\frac{25}{24}

5)

\frac{7}{8}-\frac{5}{6}=

Again, the lowest common denominator is 24. This time the denominator of the 1st fraction is 8 while the denominator of the 2nd fraction is 6, so we have to multiply the numerator of the 1st fraction by 3 and the numerator of the 2nd fraction by 4.

We get:

7\cdot 3 = 21\\5\cdot 4 = 20

So the expression will be rewritten as:

\frac{7}{8}-\frac{5}{6}=\frac{21}{24}-\frac{20}{24}=\frac{21-20}{24}=\frac{1}{24}

6)

\frac{1}{6}+\frac{7}{8}=

Here the situation is similar to the first 4 exercises: using 24 as lowest common denominator, the numerators become

1\cdot 4 = 4\\7\cdot 3 = 21

So the expression becomes

\frac{1}{6}+\frac{7}{8}=\frac{4}{24}+\frac{21}{24}=\frac{4+21}{24}=\frac{25}{24}

Learn more about fractions:

brainly.com/question/605571

brainly.com/question/1312102

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