Question

3x - 3y = -32x - y = -5​

Answer 1

For this case we must solve the following system of equations:

$3x-3y = -3\\2x-y = -5$

To solve we follow the steps below:

We multiply the second equation by -3:

$-6x + 3y = 15$

Thus, we have the equivalent system:

$3x-3y = -3\\-6x + 3y = 15$

We add the equations:

$3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4$

We look for the value of the variable "y":

$2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3$

Thus, the solution of the system is given by:

$(x, y): (- 4, -3)$

Answer:

$(x, y): (- 4, -3)$