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sergij07 [2.7K]
3 years ago
5

3x - 3y = -32x - y = -5​

Mathematics
1 answer:
Korolek [52]3 years ago
4 0

For this case we must solve the following system of equations:

3x-3y = -3\\2x-y = -5

To solve we follow the steps below:

We multiply the second equation by -3:

-6x + 3y = 15

Thus, we have the equivalent system:

3x-3y = -3\\-6x + 3y = 15

We add the equations:

3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4

We look for the value of the variable "y":

2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3

Thus, the solution of the system is given by:

(x, y): (- 4, -3)

Answer:

(x, y): (- 4, -3)

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Find (f+g)(x).
kaheart [24]

Answer:

(f+g)(x)  = x^3 - 3x + 2

Step-by-step explanation:

Find  (f+g)(x) by adding together f(x) = -3x + 2   and  g(x) = x^3:

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(f+g)(x)  = x^3 - 3x + 2                                                        

7 0
3 years ago
A livestock company reports that the mean weight of a group of young steers is 1143 pounds with a standard deviation of 88 pound
malfutka [58]

Answer:

<em>a) P(x<1200)=74.14%</em>

<em>b) P(1100<X<1250)=57.54%</em>

Step-by-step explanation:

<u>Normal Distribution</u>

The normal distribution, also known as the bell curve, is a distribution that occurs naturally in many situations of life. We use the model N(\mu,\sigma) to understand the behavior of some real-life variables. Where \mu is the mean value and \sigma is the standard deviation.

In our case, we have

\mu=1143,\ \sigma=88

And are required to find the percentage of steers whose weigh lie within a given range. We must use some sort of table or digital means to compute the values because the normal distribution cannot be calculated directly by a formula. We use the NORMDIST (or NORM.DIST) formula for Excel which gives us the left tail of the area behind the bell curve, i.e. the cumulative percentage for a give value of X. The formula has the form

NORM.DIST(x,mean,standard_dev,cumulative)

a) X<1200

The formula is used with the following parameters

NORM.DIST(1200,1143,88,true)

and we get

P(X

b) We need to compute P(1100<X<1250). To do this, we calculate both left tails and the subtract them

NORM.DIST(1100,1143,88,true)=0.3125

NORM.DIST(1250,1143,88,true)=0.8880

P(1100

\boxed{P(1100

6 0
3 years ago
A boat drops an anchor 75 feet to the bottom of a lake. A sunken treasure chest lies at the bottom of the lake, 40 feet away fro
Reil [10]
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet

Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat

By Pythagoras theorem
AC^2 = AB^2 + BC^2

(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)

AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)

Therefore they have cover a distance of 25 * (under root 11)
5 0
3 years ago
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