Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Let's take a look at the first few numbers in the sequence based on the given rule:
Inspecting this pattern it seems like the power
is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be
. We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as
Where
is the nth number in our sequence.
Answer:
well I think the question's not complete but if that's the question then 9 boxes would cost about $63 dollars. since some stores have a sale, you should add the word 'about' or 'around' with the answer. hope it was helpful ))
To answer this i need a little more info but it's probably going to be 30 miles.
