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Pani-rosa [81]
3 years ago
11

Multiply. Express your answer in simplest form. 9 1/6 × 1 1/11

Mathematics
2 answers:
Sati [7]3 years ago
8 0

Answer:

10

Step-by-step explanation:

First convert the fractions.

9 1/6 to 55/6  and 1 1/11 to 12/11

With these fractions, you can cross out 11 and 6.

55   times    12             5   ×    2

6                   11              1   ×    1

This equals 10/1 or 10

Novay_Z [31]3 years ago
4 0

The answer is... 10. YA!

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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

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As you can see your solution is the last option.

3 0
3 years ago
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