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3 years ago

Find the distance between the two points in simplest radical form (4,6) and (-2,9)

1 answer:

6 0

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{(-2-4)^2+(9-6)^2}\implies d = \sqrt{(-6)^2+3^2}\implies d = \sqrt{36+9} \\\\\\ d = \sqrt{45}\implies d = \sqrt{9\cdot 5}\implies d=\sqrt{3^2\cdot 5}\implies d = 3\sqrt{5}$

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Express each ratio as a unit rate. Round to the nearest tenth, if necessary.

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2 years ago

What's the sum of 6(-2.1k - 2) + (7k + 5)

jok3333 [9.3K]

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2 years ago

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15 1/3÷3 5/6 explain how

mylen [45]

First, view how i converted the mixed fraction in the picture.

Next, we need to get the same denominator,
46/3 divided by 23/6, 6 and 3; all we do is times 3 by 2 to get 6 and time six by 1 to stay the same.(Tip: every thing you do to the denominator you do to the numerator.
= 46*3=92 , 3*2=6 other fraction, 23*1=23 , 6*1=6

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2 years ago

You deposit $1500 in an account earning 3.5% interest compounded monthly.

guapka [62]

Answer:

Answer:

\sf (x+14)^2+(y+5)^2=149(x+14)2+(y+5)2=149

Step-by-step explanation:

Standard equation of a circle: \sf (x-a)^2+(y-b)^2=r^2(x−a)2+(y−b)2=r2

(where (a, b) is the center and r is the radius of the circle)

Substitute the given center (-14, -5) into the equation:

\sf \implies (x-(-14))^2+(y-(-5))^2=r^2⟹(x−(−14))2+(y−(−5))2=r2

\sf \implies (x+14)^2+(y+5)^2=r^2⟹(x+14)2+(y+5)2=r2

Now substitute the point (-7, 5) into the equation to find r²:

\sf \implies ((-7)+14)^2+(5+5)^2=r^2⟹((−7)+14)2+(5+5)2=r2

\sf \implies (7)^2+(10)^2=r^2⟹(7)2+(10)2=r2

\sf \implies 149=r^2⟹149=r2

Final equation:

\sf (x+14)^2+(y+5)^2=149(x+14)2+(y+5)2=149

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2 years ago

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3 years ago

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