The gaps in the area needs to be closed so the data you use is lenient
7.5 would be my best guess
-3x^2-2x (+-)6=0
ax^2+bx+c
a=-3
b=-2
c= either positive or negative 6 (there is no plus or minus in your question.)
What are the answer choices? It might help.
Answer:
y = 2/3x +6 for x< -3
y = 2/3x +1 for x> 3
Step-by-step explanation:
The graph is a line for x < -3
( - 6,2) and ( -3,4)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point ( -6,2)
y -2 = 2/3(x - -6)
y -2 = 2/3(x +6)
y-2 = 2/3 x +4
y = 2/3x +6 x< -3
The graph is a line for x > 3
(3,3) and ( 6,5)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 5-3)/(6-3) = 2/ (3) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point (6,5)
y -5 = 2/3(x - 6)
y-5 = 2/3 x -4
y = 2/3x +1 x> 3
