At x = -4 and -8
Take the derivative of the given equation to find rate of change of the graph.
f'(x) = 6x^2 + 72x + 192
At a horizontal tangent, f'(x) = 0, so set the equation equal to 0 and solve. Eventually you get x = -4 and -8
Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Answer:
is there an image of the frequency table attached? whats the question
Step-by-step explanation:
We can consider east and north direction as x and y axes respectively.
latitude 0 and longitude 0 be the origin.
Let 'a' be the total way around the world
so, if I travel east 1/3 of the way around the world, x co-ordinate = 1/3 a
if I travel north 1/3 of the way around the world, y co-ordinate = 1/3 a
So the coordinates of your new location are(1/3 a, 1/3 a)
