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almond37 [142]
3 years ago
15

PLEASE HELP PICTURE PROVIDED

Mathematics
2 answers:
Nataly_w [17]3 years ago
8 0
The answer is A. $6.50
Tamiku [17]3 years ago
4 0

Answer:

the answer is A 6.50

Step-by-step explanation:

becasue u just have to look at the line and find the one hour

You might be interested in
What is 9/10-6/10 or can you not do it?
Olin [163]

Answer:

3/10

Step-by-step explanation:

9-6=3

both fractions have the same denominator so they keep it

9/10 - 6/10 = 3/10

<h3>3/10 is also 0.33</h3>
5 0
2 years ago
In 2000, the total population of the U.S. was 281.4 million people. In 2010, it was 308.7 million people. What is the average ra
kifflom [539]

Answer:

2.73 million people per year

Step-by-step explanation:

Turn sentences into coordinates/points:

In 2000, 281.4 million people

  • (x₁, y₁) = (2000, 281.4)

In 2010, 308.7 million people

  • (x₂, y₂) = (2010, 308.7)

Rate of population per year:

\sf \dfrac{y_2 - y_1}{x_2- x_1} \ \  where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points

\rightarrow \sf \dfrac{308.7-281.4}{2010-2000}

\rightarrow \sf 2.73 \ million \ people

5 0
1 year ago
3 different numbers which are all equivalent to 10
Zolol [24]

Answer:

2 4 6

Step-by-step explanation:

3 0
3 years ago
Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume
Sphinxa [80]

Answer: (1.55, 6.45)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline\ {x}\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Sample size : n=41

Sample mean : \overline{x}=4.0\text{ kg}

Standard deviation : \sigma=6.1\text{ kg}

Then, 99% confidence interval for population mean will be :_

4\pm\ (2.576)\dfrac{6.1}{\sqrt{41}}\\\\\approx4\pm2.45\\\\=(4-2.45, 4+2.45)=(1.55, 6.45)

8 0
3 years ago
Is KLMN below a rectangle?
8_murik_8 [283]
Should be C right? A rectangle demands that the diagonals are congruent
6 0
3 years ago
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