Determine if AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯ are parallel, perpendicular, or neither. Given: A (−1, 3), B (0, 5), C (2, 1), D (6, −1)
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Answer:
- Mean = 26.24
- Median = 27
- Mode = 32
- Range = 38
Step-by-step explanation:
Plotting the original data from leaf plot
<em><u>Finding Mean:</u></em>
The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:
= 26.24
Therefore, the range = 26.24.
<u>Finding Median:</u>
The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.
Ordering the data from least to greatest, we get:
9 11 12 12 14 17 25 25 27 32 32 32 33 35 41 42 47
So, the median is 27 .
<em><u>Finding Mode: </u></em>
The mode of a set of data is the value in the set that occurs most often.
Ordering the data from least to greatest, we get:
9 11 12 12 14 17 25 25 27 32 32 32 33 35 41 42 47
We see that the mode is 32.
<em><u>Finding Range:</u></em>
The range is the difference between the highest and lowest values in the data set.
Ordering the data from least to greatest, we get:
9 11 12 12 14 17 25 25 27 32 32 32 33 35 41 42 47
The lowest value is 9.
The highest value is 47.
The range = 47 - 9 = 38
Your question can be quite confusing, but I think the gist of the question when paraphrased is: P<span>rove that the perpendiculars drawn from any point within the angle are equal if it lies on the angle bisector?
Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector
Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector