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ira [324]
3 years ago
6

The measurements obtained for the interior dimensions of a rectangular box are 200 cm by 200 cm by 300 cm. If each of the three

measurements has an error of at most 1 cm, which of the following is closest to the maximum possible difference, in cubic cm, between the actual capacity of the box and the capacity computed using these measurements?A. 100,000.B. 120,000.C. 160,000.D. 200,000.E. 320,000.
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

C. 160,000

Step-by-step explanation:

Given that the measurements obtained for the interior dimensions of a rectangular box are 200 cm by 200 cm by 300 cm.

Also given that each of the three measurements has an error of at most 1 cm

COnsider the worst case where each dimension is increased by 1 cm

Then we measure the dimensions as 201 , 201 and 301

So volume would be measured as

201*201*301\\= 12160701 cubic cm

Actual volume of the box = 200*200*300\\=12000000 cubic cm

Difference maximum possible = 160701 cubic cm

Out of the five options given option C is nearest to this value

So answer is

C. 160,000

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Answer:

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Step-by-step explanation:

* Lets explain how to factorize the difference of two cubes

- If we want to factorize x³ - y³

- The binomial x³ - y³ is different of two cubes, because x³ is cube x

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- The difference of two cubes has two factors one two two terms and

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→ Then the first factor is (x - y)

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→ square x

→ square y

→ Multiply x and y and put them between x² and y² with opposite sign

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* Lets do the same with 1331x³ - 8y³

∵ \sqrt[3]{1331x^{3}}=11x

∵ \sqrt[3]{8y^{3}}=2y

∴ The first factor is (11x - 2y)

∵ (11x)² = 121x²

∵ (2y)² = 4y²

∵ 11x × 2y = 22xy

∵ The sign of first factor is (-)

∴ The second factor is (121x² + 22xy + 4y²)

∴ <em>The factor is 11x - 2y  </em>

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garik1379 [7]
<h3>Given:</h3>
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