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pshichka [43]
3 years ago
6

20. Each student read 41 pages in December

Mathematics
2 answers:
Artemon [7]3 years ago
7 0
I would need to know how many students there are. Unless youre looking for an equation in which case its: 41x
azamat3 years ago
3 0

Answer:

I think 1,271 pages idk

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Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
Factor completely: 10ax + 5bx - 8ay - 4by
kiruha [24]
The answer is (5x - 4y)(2a + b)

10ax + 5bx - 8ay - 4by = 10ax + 5bx - (8ay + 4by) =<span>
                                      = 5x * 2a + 5x * b - (2a * 4y + b * 4y) =
                                      = 5x(2a + b) - 4y(2a + b) = 
                                      = (5x - 4y)(2a + b)</span>
4 0
3 years ago
Which two triangles are congruent ? Complete the congruence statement . Please don’t be wrong I’ll
lukranit [14]

Answer:

ΔHFG≅ΔSUT

Step-by-step explanation:

You just have to match up the sides and the angle.It's easier to color code them.

For example:

Segment SU would be congruent with HF. (both would be blue, just example color)

Angle U is congruent to angle F (red)

UT congruent to FG (green)

6 0
3 years ago
Determine whether The given segments have the same length. Justify your answer
Semenov [28]

We know the distance formula is

\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }

9)

Here A( -4,2) and B(1,4)

So length of AB

= \sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}

Also C(2,1)

Length of BC

= \sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}

So we can see that length of AB is not equal to length of BC

11.

Now AB = \sqrt{29}

Also C(2,-1) & D(4,4)

Length of CD

= \sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}

Yes AB = CD

5 0
3 years ago
What is the total surface area of the prism?
Trava [24]
The total surface area of this prism is 480.
7 0
3 years ago
Read 2 more answers
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