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iren2701 [21]3 years ago

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Step-by-step explanation:

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$f(n) =4 + f(n-1) \\for\ n>2$

Step-by-step explanation:

Given

$f(1)=2\\ f(2)= 6\\ f(3)= 10\\ f(4)= 14\\ f(5)= 18$

Required

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First, we need to solve common difference (d)

$d = f(n) - f(n-1)$

Take n as 2

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$d = 6 - 2$

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$f(4) = 10 + 4 = f(3) + 4$

$f(5) = 14 + 4 = f(4) + 4$

Represent the function as $f(n)$

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Reorder

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