We have by the intermediate value theorem that if a continuous function takes values both above and below zero at 2 points, there is a zero of the function in-between. We have that polynomials are continues. Let's calculate f(-6) and f(-5). f(-6)=-36 while f(-5)=-1. Thus, we cannot conclude that there is a root between them.
F(-2)=8, f(-1)=-1, so there is a flip; a zero must exist between them.
F(1)=-1, f(2)=20, so again there is a change of signs.
f(-5)=-1, f(-4)=14 so there is a root still.
We have that the only choice that does not have a root between the integers is choice a.
Answer:
C) 1/3
Step-by-step explanation:
First look at equation: 3x+y=1
re-write as y=mx+b
y=-3x+1
so the slope of this equation i s-3
so if a line is perpendicular to the above equation,
its slope will be reciprocal negative which is 1/3
Answer: I think it is negative.
Step-by-step explanation: When you add a negative to a negative you still have a negative.
Answer:
robux
Step-by-step explanation:
1p robux ca rjs djsj
So you will need to solve for x and y before evaluating 2x+y....
2x-y=9, y=2x-9 now this will make 4x^2-y^2=171 become:
4x^2-(2x-9)^2=171
4x^2-(4x^2-36x+81)=171
36x-81=171
36x=252
x=7, now we can use 2x-y=9 to solve for y...
2(7)-y=9
14-y=9
-y=-5
y=5
now we know that x=7 and y=5, 2x+y becomes:
2(7)+5
14+5
19
