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lbvjy [14]
3 years ago
12

Can anyone solve these? Thanks.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0
Graph A is a linear function, while Graph B is an exponential funtion.
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joja [24]
Stars form from an accumulation of gas and dust, which collapses due to gravity and starts to form stars. The process of star formation takes around a million years from the time the initial gas cloud starts to collapse until the star is created and shines like the Sun.Jul 4, 2019
4 0
3 years ago
If EFGH is a parallelogram, what is the value of x?
Vladimir [108]

Based on the property of the consecutive angles of a parallelogram, the value of x is calculated as: E. 37.

<h3>What are the Properties of the Angles of a Parallelogram?</h3>

In a parallelogram, the angles that are opposite to each other are congruent while consecutive angles are supplementary.

Angles F and G are consecutive angles and are therefore supplementary (have a sum of 180 degrees.)

Angle F + angle G = 180

4x - 2 + 34 = 180

4x + 32 = 180

4x = 180 - 32

4x = 148

x = 148/4

x = 37

Value of x is: E. 37.

Learn more about parallelogram on:

brainly.com/question/3050890

#SPJ1

4 0
2 years ago
What is the base of the triangle? A=36mm(2) H= 6mm B=?
Maurinko [17]

Answer:

Area formula=b*h÷2

b=a÷h*2

b=12

Step-by-step explanation:

So if you multiply the base and height to find a triangle, you'd get the area of a rectangle instead so if you divide by 2, you'd get the area of a triangle

To find the base, you'd reverse the process. You'd divide the area by the height and multiply by 2.

36÷6=6

6*2=12

Hope that helps!

4 0
3 years ago
Write an equation in standard form of the hyperbola described.
marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}

5 0
2 years ago
In which quadrant is (1/2, -1.8)? Quadrant I Quadrant II Quadrant III Quadrant IV
Nadya [2.5K]

Answer:

(1/2, -1.8) belongs in quadrant 4

quadrant 4 is a (positive, negative)

7 0
4 years ago
Read 2 more answers
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