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lbvjy [14]
3 years ago
12

Can anyone solve these? Thanks.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0
Graph A is a linear function, while Graph B is an exponential funtion.
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Which of the following is a radical equation?
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Given that a polynomial has a constant term and at least one other term what is the minimum number of possible zero values based on the rational zero test? a-0 b-2 c-3 d-4

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What time is 5 1/4 hours after 7:00?
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Seven add five is 12 . A clock has four quarters , the first quarter is fifteen minutes.
Therefore, 5 1/5 hours after 7:00 = 12:15
4 0
3 years ago
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A carpenter is cutting down dowels from a piece of wood that is 10 inches long. How many 1/2-inch dowels can the carpenter cut?
Reika [66]
He can cut 5, because 10in divided by 2 is 5.
6 0
3 years ago
Read 2 more answers
Resuelve:
jok3333 [9.3K]

Answer:

A partir del problemas vamos a crear una ecuación donde X es una docena de huevos y Y una libra de mantequilla

entonces: 4 docenas de huevos y 3 libras de mantequilla es igual a 14.100

en mi primera ecuación seria: 4X + 3Y = 14.100

ahora haremos la segunda ecuacion: tres docenas y 1 libra de mantequilla

en mi segunda ecuación seria: 3X + 1Y = 8.700 el plan es sumar las dos ecuaciones pero yo quiero que al sumarlas la variable "Y" desaparezca así que mi segunda ecuación la voy a multiplicar pór (-3) quedándome todo así:

primera ecuación: 4X + 3Y = 14.100

segunda ecuacion multiplicada por -3: -9X - 3Y = -26.1

al sumarlas obtengo como resultado: -5X = -12

resolviendo esa ecuacion obtengo que X=  

X=2.4

luego reemplazas X en la primera ecuación: 4X + 3Y = 14.100

reemplazando seria: 4 x (2.4) + 3Y =14.100

9.6 + 3Y = 14.1000

3Y= 14.100 - 9.6

Y=  

Y=1.5

entonces concluimos que la docena de huevos cuesta 2.4 $ y la libra de mantequilla 1.5 $

Step-by-step explanation:

4 0
3 years ago
I NEED A ANSWER FAST PLEASE HELP
NikAS [45]

Answer:

Elevation in boiling point is mathematically expressed as

ΔTb = Kb X m

where Kb =  boiling point elevation constant =  2.53°c/m (for benzene)

m = molality of solution = 3.47 m (given)

∴ ΔTb = 2.53 X 3.47

          = 8.779 oC

But, boiling point of benzene = 80.1 oC

∴ Boiling point of solution = 88.879 oC

Now, Depression in freezing point = ΔTf = Kf X m

where, Kf = freezing point depression constant = 5.12°c/m (for benzene)

∴ ΔTf = 5.12 X 3.47

        = 17.766 oC

But freezing point of benzene = 5.5 oC

∴ Freezing point of solution = -12.266 oC

3 0
3 years ago
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