Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
2 answers:
sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
<u>Step-by-step explanation: </u>
We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)
Given sequence is an AP with following parameters as :
So , Let's calculate how many terms are there as :
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Sum of an AP is :
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Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250
The sum of the given sequence is -25500.
<u>Step-by-step explanation: </u>
The given Arithmetic sequence is 46 + 42 +38... +(-446) +(-450).
The first term of the sequence = 46 The last term of the sequence = -450 The common difference ⇒ 42 - 46 = - 4 <u>To find the number of terms in the sequence : </u>
The formula used is
where,
n is the number of terms. is the late term which is -450. is the first term which is 46.d is the common difference which is 4. Therefore,
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∴ The number of terms, n = 125.
<u>To find the sum of the arithmetic progression : </u>
The formula used is
where,
S is the sum of the sequence. is the first term which is 46. is the late term which is -450.Therefore,
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∴ The sum of the given sequence is -25500.
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It would be .01 or .0y in your case
Yes, It Is A Full Equation.
4 x 2/4
2/4 can be reduced to 1/2
Now you have 4 x 1/2
Multiply 4 by 1 then divide by 2:
4 x 1 = 4
4/2 = 2
The answer is 2