Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that
you can clear the intersection from the formula
and apply it for the given events:


c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:

Then:


I hope it helps!
Answer:
(8)
and 
(9)
and 
(10)
and 
Step-by-step explanation:
Given [Missing from the question]

Required
Write a system of linear equations
The solutions to this question is open and have different solutions
Solving (8) (-6,-2)
Let the equations be: x + y and 2x - y

--- (1)

-- (2)
So, the equations are:
and 
Solving (9) (-12, 18)
Let the equations be: 3x - y and 4x + y




So, the equations are:
and 
Solving (9): (2,0)
Let the equations be: x + y and x - y




So, the equations are:
and 
Step-by-step explanation:
since KLJ is a parallelogram, it can be split into 2 congruent triangles, as seen above. The angles remain the same, so we know angle KJL is also 25 degrees. Using the triangle angle sum theorem (all sides of a triangle add up to 180 degrees), we can determine the missing angle measure is 25 degrees. It would have been nice if the question told us JKLM was also a rhombus.
Answer:
c. D: {1, 2, 3, 4, 5}
Step-by-step explanation:
The domain of a function includes values of x that are in the given table of values of the given function.
The range, on the other hand, includes all set of values of y, given in the table of values.
Thus, for the table of values above:
Domain would be [1, 2, 3, 4, 5]
Range would be [a, b, c, d, e]
The domain of the function can be represented as:
D: {1, 2, 3, 4, 5}