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Mice21 [21]
3 years ago
8

There is a six sided polygon in which the first side is a line, the second side is a line segment, the third side is an arrow wh

ose head is in the direction of the point of intersection of second side, the fourth side is a line, the fifth side is a line segment and the last side is an arrow whose head is in the direction of the point of intersection of fifth side. The exterior angle formed by the first and sixth side is labeled as 1, the exterior angle formed by first and second side is labeled as 2, the exterior angle formed by second and third side is labeled as 3, the exterior angle formed by third and fourth side is labeled as 4, the exterior angle formed by the fourth and fifth side is labeled as 5, and the exterior angle formed by the fifth and sixth side is labeled as 6. The interior angle of fifth and sixth side is a right angle.
If ∠1 ≅ ∠2 ≅ ∠3, ∠4 ≅ ∠5, and m∠4 = m∠3 + 10°, What is m∠5?
Mathematics
1 answer:
Phantasy [73]3 years ago
6 0
I need points Thanks
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(3x – 70) (3y+40) 120 x
enyata [817]

Answer:

3x-70

Step-by-step explanation:

(3y+40 ) 120x is the answer of that question answer

4 0
3 years ago
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Congress regulates corporate fuel economy and sets an annual gas mileage for cars. A company with a large fleet of cars hopes to
attashe74 [19]

Answer:

a) Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

b) X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c) t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

p_v =P(t_{(49)}>2.81)=0.0035  

d) If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e) The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

\bar X=32.12 represent the sample mean  

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =30.2 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

a. Define the parameter and state the hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 30.2 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

b. Define the sampling distribution (mean and standard deviation).

Let X the random variable who represent the variable of interest. And we know that the distribution for X is:

X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c. Perform the test and calculate P-value

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(49)}>2.81)=0.0035  

d. State your conclusion.

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e. Explain what the p-value means in this context.

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

6 0
3 years ago
A deer population is declining by 2.2% per year. The population can be modelled using the formula p = 240(0.978)n , where P is t
ale4655 [162]

Answer:

The current deer population is 240.

Step-by-step explanation:

The expression given models a exponential decay follows:

p(n) = 240*(0.978)^n

For every year that passes since the beginning of the count the population is 0.978 of the year prior. Assuming that the count starts at this year, then "n" is equal to 0, applying this value of n to the formula gives us:

p(0) = 240*(0.978)^0\\p(0) = 240*1 = 240

The current deer population is 240.

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4 years ago
How many seconds are in two weeks?
podryga [215]

Answer:

This conversion of 2 weeks to seconds has been calculated by multiplying 2 weeks by 604,800 and the result is 1,209,600 seconds.

Step-by-step explanation:

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3 years ago
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Which expression is equivalent to the following expression? 10x + 3(8 - 7x)
Paladinen [302]
It is -11x + 24 because you multiply the numbers in the parentheses by 3 then collect like terms 10x +24 - 21x then you do 10x minus 24x and you get -11x+24
7 0
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