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Mice21 [21]
3 years ago
8

There is a six sided polygon in which the first side is a line, the second side is a line segment, the third side is an arrow wh

ose head is in the direction of the point of intersection of second side, the fourth side is a line, the fifth side is a line segment and the last side is an arrow whose head is in the direction of the point of intersection of fifth side. The exterior angle formed by the first and sixth side is labeled as 1, the exterior angle formed by first and second side is labeled as 2, the exterior angle formed by second and third side is labeled as 3, the exterior angle formed by third and fourth side is labeled as 4, the exterior angle formed by the fourth and fifth side is labeled as 5, and the exterior angle formed by the fifth and sixth side is labeled as 6. The interior angle of fifth and sixth side is a right angle.
If ∠1 ≅ ∠2 ≅ ∠3, ∠4 ≅ ∠5, and m∠4 = m∠3 + 10°, What is m∠5?
Mathematics
1 answer:
Phantasy [73]3 years ago
6 0
I need points Thanks
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Answer:

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Step-by-step explanation:

10x = 105 - (12x - 247) //Distribute - sign

10x = 105 - 12x + 247 // Add 12x & combine like terms

10x + 12x = 352

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x = 16

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In this case, the variable is x.

The number that comes before x is 7, so 7 is the coefficient.

Hope this helps! :)

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