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Lady_Fox [76]
3 years ago
6

Plz help will give brainliest

Mathematics
1 answer:
den301095 [7]3 years ago
6 0

Answer:

5 campgrounds

Belleville is furthest south

The volcano’s name is Sue

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See attached picture, is there a way to enter equations or algebraic symbols?
coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}

(A)

\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

(B)

\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

(C)

\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

(D)

\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

5 0
1 year ago
Equation A:
pentagon [3]

The answer is –x + 5 = 6x - 2. This is because of the Transitive Property.

You most likely remember the transitive property as "if a = b and b = c, then a = c." In this case, if y = -x + 5 and y = 6x - 2, then -x + 5 = 6x - 2.

4 0
3 years ago
Solve. (K+1)(k-5)=0<br> Explin how to solve ???
Anna71 [15]
Alright remember, if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0. 
k+1=0
k-5=0
Set the first factor equal to 0 and solve
k=-1
Set the next factor equal to 0 and solve
k=5
The final solution is all the values that make (k+1)(k-5)=0 true. 
k=-1, 5

Hope this helped you out :)
5 0
3 years ago
Read 2 more answers
Solve each system by elimination. substitution by multiplication
umka2103 [35]
M = 135/19 and n = -5/19

You have to give them like terms so that when you eliminate they cancel out and you can solve. The easiest way to do so is by multiplying the top equation by -4 and the bottom by 3. 
4 0
3 years ago
Write each literal term in exponential form kkkknn
emmasim [6.3K]
K⁴n²


..................................
7 0
3 years ago
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