Answer: T = 10p
Step-by-step explanation: Since we don't know what is the total weight, we put the an variable, T to represent the total weight. The 10p means that the poilce officer gained 10 Pounds.
Answer:
=38.192x
Step-by-step explanation:
I hope this helps you
Answer:
3x + 12
Step-by-step explanation:
Yes it is a function. It passes the vertical line test. In other words, it is impossible to draw a single vertical line through more than one point on the V shaped graph. Any input leads to exactly one output.
The domain is the set of all real numbers. This is because we can plug in any x value leading to some specific y value. There are no holes or gaps or jumps to indicate we must restrict any given x value. The domain would not be the set of whole numbers only because values between the whole numbers (eg: decimal values like x = 2.75) work just fine.
The range is the set of y values such that y is either 0 or larger than 0. In short,
the range is ![y \ge 0](https://tex.z-dn.net/?f=y%20%5Cge%200)
. Notice how any point on the V shaped graph has a y coordinate that is either 0 or larger than 0. It is impossible to get a y value that is negative.
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In summary,
Yes it is a function
Domain: all real numbers
Range:
![y \ge 0](https://tex.z-dn.net/?f=y%20%5Cge%200)
So
the answer is choice B
For this case we have the following polynomials:
![-x ^ 2 + 9\\-3x ^ 2 - 11x + 4](https://tex.z-dn.net/?f=%20-x%20%5E%202%20%2B%209%5C%5C-3x%20%5E%202%20-%2011x%20%2B%204%20%20)
Adding the polynomials we have:
![(-x ^ 2 + 9) + (-3x ^ 2 - 11x + 4)](https://tex.z-dn.net/?f=%20%28-x%20%5E%202%20%2B%209%29%20%2B%20%28-3x%20%5E%202%20-%2011x%20%2B%204%29%20%20)
Rewriting we have:
![x ^ 2 (-1-3) - 11x + (9 + 4)](https://tex.z-dn.net/?f=%20x%20%5E%202%20%28-1-3%29%20-%2011x%20%2B%20%289%20%2B%204%29%20%20)
Therefore, the result of the sum is:
![-4x ^ 2 - 11x + 13](https://tex.z-dn.net/?f=%20-4x%20%5E%202%20-%2011x%20%2B%2013%20%20)
Answer:
the sum of the polynomials is:
![-4x ^ 2 - 11x + 13](https://tex.z-dn.net/?f=%20-4x%20%5E%202%20-%2011x%20%2B%2013%20%20)
option 2