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Gekata [30.6K]
3 years ago
9

Compare -0.3 and -1/3

Mathematics
1 answer:
zaharov [31]3 years ago
4 0
The answer is -0.1 I believe
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HELP ME! FAST! Please help me! ASAP! PLEASE! SOMEONE HELP ME!
Harrizon [31]
I hope this helps you

5 0
2 years ago
Kareem wrote the values shown below.
sweet [91]

Answer:  Option 'B' is correct.

Step-by-step explanation:

Since we have given that

[3.2] [2.7] [2.9] [4.8]

Since they are all of greatest integer functions i.e.

f(x) = [x]

It is known as greatest integer function whose value is always less than or equal to 'x'.

So, [3.2]=3

[2.7]=2

[2.9]=2

[4.8]=4

so, we can see that [2.7] and [2.9] is a equivalent pair.

Hence, Option 'B' is correct.

4 0
3 years ago
Read 2 more answers
Sandra has a $20 itunes gift card and spends $3 each month. Which of the following functions models how much money Sandra has on
SCORPION-xisa [38]

Answer:

x3-20

Step-by-step explanation:

x stands for the month 3 is the money that she is spending each month if you multiply those together you get the amount of money she has spent over x amount of months minus the 20 dollars on her gift card

8 0
2 years ago
Owen runs 37 miles every 2 weeks. Enter the number of miles Owen runs in 12 weeks
Shtirlitz [24]
I think it’s 222 because he runs 18.5 miles every week and 18.5 x 12 = 222
3 0
3 years ago
Find the unit tangent vector T(t) to the curve r(t) = [sin(t), 1 + t, cos(t)] when t = 0.
ss7ja [257]

Compute the derivative of \mathbf r(t) at t=0 - this will be the tangent vector - then normalize it by dividing it by its magnitude to get the unit tangent vector \mathbf T(t).

\mathbf r(t) = \langle \sin(t), 1+t, \cos(t) \rangle \implies \dfrac{d\mathbf r}{dt} = \langle \cos(t), 1, -\sin(t) \rangle \implies \dfrac{d\mathbf r}{dt}(0) = \langle 1, 1, 0 \rangle

\|\langle1,1,0\rangle\| = \sqrt{1^2+1^2+0^2} = \sqrt2

\implies\mathbf T(0) = \dfrac{\langle1,1,0\rangle}{\sqrt2} = \boxed{\left\langle \dfrac1{\sqrt2}, \dfrac1{\sqrt2}, 0\right\rangle}

7 0
1 year ago
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