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mixer [17]
3 years ago
14

WILL GIVE A BRAINLIEST!!

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
4 0
If the vertex is at the maximum point they dy/dx=0 at that point...

dA/dx=-2x+4

dB/dx=-2x+8

dC/dx=2x-4

dD/dx=2x-8

So both B and D have a zero velocity at x=4, but only B is equal to 3 when x=4

B. is the correct quadratic with the vertex at (4,3)
scoray [572]3 years ago
3 0

Answer:

<h2>B.</h2><h2>  y=-x^{2} +8x-13</h2>

Step-by-step explanation:

We know that the vertex of the parabola is

V(4,3)

That means this points is being intercept by the parabola. In other words, the function that represents this parabola has to have this relation, when x=4, y=3.

So, you can observe that the second choice has a function that follows this relation. Let's see

y=-x^{2} +8x-13

So, for x=4

y=-(4)^{2} +8(4)-13\\y=-16+32-13\\y=3

Therefore, function B is the answer because it includes the vertex at its relation.

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What is the factored form of X^9+27 A (x^3-3)(x^6+3x^3+9) B(x^3+3)(x^6-3x^3+9) C(x-3)^3(x^6+3x^3+9) D(x+3)^3(x^6-3x^3+9)​
irinina [24]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
Explain how to subtract 247 from 538
forsale [732]
538
-247
------
8-7=1
Cross out 5 and make it 4. Make 3 into 13. 13-4=9
4-2=2

The answer is: 291
4 0
3 years ago
Compare the two expressions
Art [367]
Yes, they are equivalent
6+7-5=8. -5+10+3=8
8 0
3 years ago
If a line has a slope of 9/5. If one of the points on the line is (-10, -16), which could be another point?
zlopas [31]

Answer:

(–5, –7)

Step-by-step explanation:

From the question given above, the following data were obtained:

Slope = 9/5

Coordinate 1 = (–10, –16)

x₁ = –10

y₁ = –16

Coordinate 2 = (x₂, y₂)

Next, we shall determine the change in x and y coordinate. This can be obtained as follow:

Slope = change in y–coordinate / change in x–coordinate

Slope = Δy / Δx

Slope = 9/5

9/5 = Δy / Δx

Thus,

Δy = 9

Δx = 5

Next, we shall determine the second coordinates as follow:

Δy = y₂ – y₁

Δx = x₂ – x₁

For x–coordinate:

x₁ = –10

Δx = 5

Δx = x₂ – x₁

5 = x₂ – (–10)

5 = x₂ + 10

Collect like terms

x₂ = 5 – 10

x₂ = – 5

For y–coordinate:

y₁ = –16

Δy = 9

Δy = y₂ – y₁

9 = y₂ – (–16)

9 = y₂ + 16

Collect like terms

y₂ = 9 – 16

y₂ = – 7

Coordinate 2 = (x₂, y₂)

Coordinate 2 = (–5, –7)

6 0
3 years ago
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