Answer:

Step-by-step explanation:
Total number of students
Students wearing brown shoes
Students wearing black shoes
Number of students wearing black or brown shoes
Number of students not wearing brown or black
Fraction of students not wearing brown or black
Answer:
Minimum surface area =
Step-by-step explanation:
We are given that
Width of container=x cm
Length of container=2x cm
Volume of container=
We have to find the minimum surface areas that this container will have.
Volume of container=



Surface area of container=
Because the container does not have lid
Surface area of container=

Differentiate w.r.t x


Substitute 





Again differentiate w.r.t x

Substitute x=3.4

Hence, function is minimum at x=3.4
Substitute x=3.4
Then, we get
Minimum surface area =
So you would break 247 in to 200,40and 7
u would break 38 into 30 and 8 . so when you as then together you get and sum of 285 .so do you know the strategy now ??
Answer:
a-10
b-8
c-5
d... draw 3 circles, one for people who like just skateboarding, roller skating, and neither. Then in the skateboarding section put 10, and for roller skating add 8. In between roller skating and skateboarding add 5. In the neither circle write 8.
solution:
The probability mass function for binomial distribution is,
Where,
X=0,1,2,3,…..; q=1-p
find the probability that (p∧ ≤ 0.06) , substitute the values of sample units (n) , and the probability of nonconformities (p) in the probability mass function of binomial distribution.
Consider x to be the number of non-conformities. It follows a binomial distribution with n being 50 and p being 0.03. That is,
binomial (50,0.02)
Also, the estimate of the true probability is,
p∧ = x/50
The probability mass function for binomial distribution is,
Where,
X=0,1,2,3,…..; q=1-p
The calculation is obtained as
P(p^ ≤ 0.06) = p(x/20 ≤ 0.06)
= 50cx ₓ (0.03)x ₓ (1-0.03)50-x
= (50c0 ₓ (0.03)0 ₓ (1-0.03)50-0 + 50c1(0.03)1 ₓ (1-0.03)50-1 + 50c2 ₓ (0.03)2 ₓ (1-0.03)50-2 +50c3 ₓ (0.03)3 ₓ (1- 0.03)50-3 )
=( ₓ (0.03)0 ₓ (1-0.03)50-0 + ₓ (0.03)1 ₓ (1-0.03)50-1 + ₓ (0.03)2 ₓ (1-0.03)50-2 ₓ (0.03)3 ₓ (1-0.03)50-3 )