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AysviL [449]
3 years ago
13

Does anybody have the answer to this because I’m trying to make sure of my answer

Mathematics
1 answer:
inessss [21]3 years ago
3 0

Answer:

a-10

b-8

c-5

d... draw 3 circles, one for people who like just skateboarding, roller skating, and neither. Then in the skateboarding section put 10, and for roller skating add 8. In between roller skating and skateboarding add 5. In the neither circle  write 8.

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Help<br> help please please
Ahat [919]

Answer:

1. A

2. C

Step-by-step explanation:

I could be wrong, that's my best guess. Im so sorry if im wrong, have a good day

7 0
3 years ago
The selling price of an item is ​$ 440 After 6 months of not​ selling, it is marked down by 30​%. After another 6 months of not​
liq [111]
440...marked down by 30% means u pay 70%
70% of 440 = 0.70(440) = 308

308 ..marked down by 10% means u pay 90%
90% of 308 = 0.90(308) = 277.20 <== price after markdowns
8 0
3 years ago
372 picoseconds equal to how many femoseconds
Vlad1618 [11]

Answer:

372,000 femtoseconds

Step-by-step explanation:

<u>1 picoseconds = 1000 femtoseconds</u>

372 picoseconds = 1000 * 372 femtoseconds

1000 * 372

372,000

Answer:  372,000 femtoseconds

5 0
3 years ago
HELP PLSS<br><br><br> Write the percent as a fraction and as a decimal. <br> 3/15​%
sdas [7]

Answer:

0.2% and 1/5%

Step-by-step explanation:

Hope this helps

3 0
3 years ago
Read 2 more answers
If x = 1 is a common root of ax² +ax + 2 = 0 and x² + x + b = 0 , then ab =
vodka [1.7K]

Answer:

ab = 2

Step-by-step explanation:

Given equations

ax² +ax + 2 = 0

x² + x + b = 0

root of both the equation

x= 1

then we can plug in x = 1 in both the equation

ax² +ax + 2 = 0                        x² + x + b = 0

a*1² +a*1 + 2 = 0                        1² + 1 + b = 0

a +a + 2 = 0                                 1 + 1 + b = 0

2a + 2 = 0                                    2 + b = 0

2a = -  2                                         b = -2

a = -2/2 = -1

Thus,

a = -1

b = -2

a*b = -1*-2 = 2

ab = 2

6 0
3 years ago
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