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AysviL [449]
3 years ago
13

Does anybody have the answer to this because I’m trying to make sure of my answer

Mathematics
1 answer:
inessss [21]3 years ago
3 0

Answer:

a-10

b-8

c-5

d... draw 3 circles, one for people who like just skateboarding, roller skating, and neither. Then in the skateboarding section put 10, and for roller skating add 8. In between roller skating and skateboarding add 5. In the neither circle  write 8.

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Which choice is equivalent to the quotient shown here for acceptable values of X?
mr Goodwill [35]

The solution is shown in the photo

4 0
4 years ago
You are collecting a sample of 60 data points from a population that you know to follow an exponential distribution. It is not a
11111nata11111 [884]

Answer:

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

For this case we have a large sample size n =60 >30

The exponential distribution is the probability distribution that describes the time between events in a Poisson process.

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

5 0
4 years ago
Ton 9 of 10
MissTica
B I took it on edge so it’s correct I agree
5 0
2 years ago
Jason baked a berry pie. The recipe called for 9 ounces of blackberries, 10
gavmur [86]

Answer:

Jason would have 5 ounces of berries left. 3 ounces of blackberries and 2 ounces of raspberries.

Step-by-step explanation:

5 0
4 years ago
Will mark brainliest if help
Simora [160]
B .. i took the quiz / worksheet already .
4 0
3 years ago
Read 2 more answers
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