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Vilka [71]
3 years ago
11

Cifrele romane de la 1 pana 100 romani pls​

Mathematics
1 answer:
Kamila [148]3 years ago
8 0
Sorry I don’t understand 1-100=99 sorry
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Plzzzzzzzzz anyone helpppppp10points
BlackZzzverrR [31]

when is 9 = 15.2 - 0.537x

         9 = 15.2 - 0.537x

  -15.2      -15.2                 subtract 15.2 from both sides

      -6.2   =   -0.537x  

/-0.537           /-0.537    divide -0.537 from both sides

11.55  = x   or 12 feet round to nearest whole foot


5 0
3 years ago
A school paid $31.25 for each calculator. If the school bought x calculators, how much did they pay?
Katyanochek1 [597]

Answer:

31.25×

Step-by-step explanation:

suppose that the value of x was 3 . that would mean that they bought 3 calculators .

if one calculator is $31.25 then 3 would be $31.25× 3

the same rule would apply for x

7 0
3 years ago
12-2(n-1)=-18<br><br> aa help plzz
Luda [366]

Answer:

n=16

Step-by-step explanation:

Let's solve your equation step-by-step.

12−2(n−1)=−18

Step 1: Simplify both sides of the equation.

12−2(n−1)=−18

12+(−2)(n)+(−2)(−1)=−18(Distribute)

12+−2n+2=−18

(−2n)+(12+2)=−18(Combine Like Terms)

−2n+14=−18

−2n+14=−18

Step 2: Subtract 14 from both sides.

−2n+14−14=−18−14

−2n=−32

Step 3: Divide both sides by -2.

−2n /−2  =  −32 /−2

n=16

8 0
3 years ago
doug owns a lawn mowing service and landscaping business. the income from the business is given by the function f(x) = 2x + 54,
umka21 [38]

Answer:

For 2 parallelograms, the corresponding side lengths are 1 inch and x inches, and 2 inches and 6 inches.

Not drawn to scale

StartFraction 1 over x EndFraction = StartFraction 2 over 6 EndFraction

StartFraction 1 over x EndFraction = StartFraction 6 over 2 EndFraction

StartFraction 1 over 6 EndFraction = StartFraction 2 over x EndFraction

One-half = StartFraction 6 over x EndFraction

Step-by-step explanation:

6 0
3 years ago
Find a polynomial of degree 3 with real cofficients and zeros of -3,-1,4 for which f(-2)=24​
konstantin123 [22]

\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0

we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true

\bf x^3-13x-12=y\implies \stackrel{x = -2}{(-2)^3-13(-2)-12}=y \\\\\\ -8+26-22=y \implies 6=y

darn!! no dice.... hmmmm wait a second.... 4 * 6 = 24, if we could just use a common factor of 4 on the function, that common factor times 6 will give us 24, let's check.

\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill

4 0
3 years ago
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