Answer:
J 1
--------
x^2 -x
Step-by-step explanation:
x+1
----------
x^3-x
Factor out an x in the denominator
x+1
----------
x(x^2-1)
We can factor the terms in the parentheses because it is a difference of squares
x+1
----------
x(x-1) (x+1)
Canceling the x+1 terms
1
----------
x(x-1)
Distribute in the denominator
1
--------
x^2 -x
Answer:
8
Step-by-step explanation:
Because 16 is the diameter and to find the radius you need to divide by 2
Chlorine atom has 7 electrons in their valence shell
Answer:
f(n)=f(n-1)+f(n-2)
f(1)=1x
f(2)=1x
Step-by-step explanation:
This is the fibonacci sequence with each term times x.
Notice, you are adding the previous two terms to get the third term per consecutive triples of the sequence.
That is:
1x+1x=2x
1x+2x=3x
2x+3x=5x
3x+5x=8x
So since we need the two terms before the third per each consecutive triple in the sequence, our recursive definition must include two terms of the sequence. People normally go with the first two.
f(1)=1x since first term of f is 1x
f(2)=1x since second term of f is 1x
Yes, I'm naming the sequence f.
So I said a third term in a consecutive triple of the sequence is equal to the sum of it's two prior terms. Example, f(3)=f(2)+f(1) and f(4)=f(3)+f(2) and so on...
Note, the term before the nth term is the (n-1)th term and the term before the (n-1)th term is the (n-2)th term. Just like before the 15th term you have the (15-1)th term and before that one you have the (15-2)th term. That example simplified means before the 15th term you have the 14th and then the 13th.
So in general f(n)=f(n-1)+f(n-2).
So the full recursive definition is:
f(n)=f(n-1)+f(n-2)
f(1)=1x
f(2)=1x
Answer:
A 3^4 * 3^-4 / 3^6
C 1 / 3^6
Step-by-step explanation:
( 3^2 * 3^-2)
------------------- all the the power of 2
3^3
First simplify the numerator
We know a^b* a^c = a^(b*c)
( 3^(2+-2))
------------------- all to the power of 2
3^3
( 3^(0))
------------------- all to the power of 2
3^3
( 3^(0))
------------------- all to the power of 2
3^3
We know a^b/ a^c = a^(b-c)
3^(0-3) all to the power of 2
3^-3 all to the power of 2
3^-3 ^2
We know that a^b^c = a^(b*c)
3^(-3*2)
3^ -6
We know the negative exponent takes if from the numerator to the denominator
1 / 3^6
The other correct choice is A
3^4 * 3^-4 = 3^0 which is 1
1/3^6 is the same answer
