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leonid [27]
3 years ago
10

a farm had 35 cows if the ratio of cows to horses was 7:3 what is the combined amount of cows and horses?

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0
7x- Number\ of\ cows\\\\
3x-\ Number\ of\ horses\\\\
7x=35\ \ \ |:7\\\\
x=5\\\\
7x+3x=7*5+3*5=35+15=50\\\\
Combined\ amount\ of\ cows\ and\ horses\ is\ equal\ to\ 50.
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1. As you can tell from the function definition and plot, there's a discontinuity at x = -2. But in the limit from either side of x = -2, f(x) is approaching the value at the empty circle:

\displaystyle \lim_{x\to-2}f(x) = \lim_{x\to-2}(x-2) = -2-2 = \boxed{-4}

Basically, since x is approaching -2, we are talking about values of x such x ≠ 2. Then we can compute the limit by taking the expression from the definition of f(x) using that x ≠ 2.

2. f(x) is continuous at x = -1, so the limit can be computed directly again:

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3. Using the same reasoning as in (1), the limit would be the value of f(x) at the empty circle in the graph. So

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4. Your answer is correct; the limit doesn't exist because there is a jump discontinuity. f(x) approaches two different values depending on which direction x is approaching 2.

5. It's a bit difficult to see, but it looks like x is approaching 2 from above/from the right, in which case

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When x approaches 2 from above, we assume x > 2. And according to the plot, we have f(x) = 0 whenever x > 2.

6. It should be rather clear from the plot that

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because sin(x) + 3 is continuous at x = 0. On the other hand, the limit at infinity doesn't exist because sin(x) oscillates between -1 and 1 forever, never landing on a single finite value.

For 7-8, divide through each term by the largest power of x in the expression:

7. Divide through by x². Every remaining rational term will converge to 0.

\displaystyle \lim_{x\to\infty}\frac{x^2+x-12}{2x^2-5x-3} = \lim_{x\to\infty}\frac{1+\frac1x-\frac{12}{x^2}}{2-\frac5x-\frac3{x^2}}=\boxed{\frac12}

8. Divide through by x² again:

\displaystyle \lim_{x\to-\infty}\frac{x+3}{x^2+x-12} = \lim_{x\to-\infty}\frac{\frac1x+\frac3{x^2}}{1+\frac1x-\frac{12}{x^2}} = \frac01 = \boxed{0}

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where the last equality holds because x is approaching +∞, so we can assume x ≠ -1. Then the limit is

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6 0
2 years ago
Find the missing side lengths leave your answer as a racials simplest form
Aleksandr-060686 [28]

Answer:

m=7\sqrt3

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Step-by-step explanation:

Hi there!

We are given a right triangle (notice the 90°) angle, the measure of one of the acute angles as 60°, and the measure of the hypotenuse (the side OPPOSITE from the 90 degree angle) as 14

We need to find the lengths of m and n

Firstly, let's find the measure of the other acute angle

The acute angles in a right triangle are complementary, meaning they add up to 90 degrees

Let's make the measure of the unknown acute angle x

So x+60°=90°

Subtract 60 from both sides

x=30°

So the measure of the other acute angle is 30 degrees

This makes the right triangle a special kind of right triangle, a 30°-60°-90°  triangle

In a 30°-60°-90° triangle, if the length of the hypotenuse is a, then the length of the leg (the side that makes up the right angle) opposite from the 30 degree angle is \frac{a}{2}, and the leg opposite from the 60 degree angle is \frac{a\sqrt3}{2}

In this case, a=14, n=\frac{a}{2}, and m=\frac{a\sqrt3}{2}

Now substitute the value of a into the formulas to find n and m to find the lengths of those sides

So that means that n=\frac{14}{2}, which is equal to 7

And m=\frac{14\sqrt3}{2}, which simplified, is equal to 7\sqrt3

Hope this helps!

7 0
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