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snow_lady [41]
3 years ago
8

nick was thinking of a number nick halves the number and gets an aswer of 27.3 form an equation with x from the information

Mathematics
1 answer:
vodomira [7]3 years ago
3 0

Answer:

x÷2=27.3

Step-by-step explanation:

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Use the given transformation to evaluate the integral.
GuDViN [60]

For the transformation

\begin{cases}x=7u+v\\y=u+7v\end{cases}

the Jacobian is

\dfrac{\partial(x,y)}{\partial(u,v)}=\begin{bmatrix}7&1\\1&7\end{bmatrix}

with determinant

\det\left(\begin{bmatrix}7&1\\1&7\end{bmatrix}\right)=48

The vertices of the triangle in the u,v-plane are

(x,y)=(0,0)\implies(u,v)=(0,0)

(x,y)=(7,1)\implies(u,v)=(1,0)

(x,y)=(1,7)\implies(u,v)=(0,1)

Then the integral is

\displaystyle\iint_R(x-8y)\,\mathrm dA=-48\int_0^1\int_0^{1-v}(u+55v)\,\mathrm du\,\mathrm dv=\boxed{-448}

3 0
3 years ago
Sarah is making strings of beads in the first string she uses 3 beads and she triples the number of beads in each of the next st
xenn [34]

Answer:

She uses 243 beads for the 5th string.

Step-by-step explanation:

In this problem, we can see a pattern. If she triples the number of beads in each of the next strings, that means that we just take the last number and multiply by 3. If the first string uses 3, then:

The second uses 9, 3 * 3 = 9

The third uses 27, 9 * 3 = 27

The fourth uses 81, 27 * 3 = 81

And the 5th uses 243, 81 * 3 = 243.

6 0
4 years ago
Need help with this question! Will attach pic! A satellite is to be put into an elliptical orbit around a moon as shown below.Th
Darina [25.2K]
An equation for the ellipse ( standard form ):
x²/a²  +  y²/b² = 1
Here is:  a - semi-major axis and b - semi-minor axis.
Radius of the moon is 1,000 km and the distance from the surface of the moon to the satellite varies from 953 km to 466 km.
a = 1,000 + 953 = 1,953 km
b = 1,000 + 466 = 1,466 km
Answer:
The equation is  x² / 1,953²  + y² / 1,466² = 1
or: x²/3,814,209  +   y²/2,149,156  = 1
4 0
3 years ago
Nonsense will be reported!!​
Pavlova-9 [17]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The required additional information required to prove the Triangles congruent are :

\qquad \sf  \dashrightarrow \: 1. \: X V= FD

The Triangles will be congruent by HL congruency.

\qquad \sf  \dashrightarrow \: 2. \: MH = MI

The Triangles are congruent by LL congruency.

\qquad \sf  \dashrightarrow \: 3. \:  \angle EDC =  \angle VUC

The Triangles are congruent by HA congruency.

\qquad \sf  \dashrightarrow \: 4. \:  \angle J  =  \angle C

The Triangles are congruent by LA congruency.

5 0
2 years ago
I NEED HELP QUICKKKKK​
serg [7]
I’m pretty sure it’s the last one
5 0
3 years ago
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