Answer: Probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.
Step-by-step explanation:
Since we have given that
Mean rate defects per unit = 0.3
Since we will use "Poisson distribution":

But we need to find the probability that a randomly selected unit will contain at least two surface-finish defect.

So,

so, it becomes,

Hence, probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.
Answer:
Step-by-step explanation:
does it have to be right?
Answer:
125
Step-by-step explanation:
25 × 5 = 125
x/5 = 25 × 5 = 125
x = 125
Answer:
d= -5/3
Step-by-step explanation:
d + 4/3 = -1/3
d= -4/3 -1/3
d= -5/3
<h3>Credited balance:-</h3>



<h3>Debited amount:-</h3>


<h3>Checked amount:-</h3>



<h3>Total change in balance</h3>



Now
<h3>Current balance</h3>

