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bulgar [2K]
2 years ago
15

Geometry please help Will give the brainliest!! What is the value of the missing angle?

Mathematics
2 answers:
inessss [21]2 years ago
8 0

Answer:

its 50

Step-by-step explanation:

180-130=50

exis [7]2 years ago
4 0

Answer: The missing angle is worth 50 degrees. 180 (straight angle) - 130 (known value) = 50 degrees (unknown value)

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What is the value of x
Effectus [21]
4x+2x=180
6x= 180
Divide by 6
X= 30
7 0
2 years ago
In circle O, what is m∠MAJ? °
mr_godi [17]

See the attached figure.

m ∠KAJ = 170° &  m ∠LAM = 80°

We should know that :

m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°

∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)

∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°

But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>

∴ m ∠MAJ + m ∠MAJ = 110°

∴ 2 * m ∠MAJ = 110°

∴ m ∠MAJ = 110° ÷ 2 = 55°


<u>So, the answer is :  m ∠MAJ = 55°</u>

4 0
3 years ago
Select the correct answer
Marta_Voda [28]

Answer:

c

Step-by-step explanation:

reason for is because when you add all the like terms you end up with c

6 0
3 years ago
What is the y-intercept in the equation y=8x+6
lisabon 2012 [21]

Answer:

(0,6) or 6

Step-by-step explanation:

To find the y-intercept look at the last variable you have, which in this case is 6. Glad to help :)

7 0
2 years ago
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
3 years ago
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