What times what is equals 455 in prime numbers

Can someone answer each step of this correctly?

Burka [1]

About Slope - Intercept Form:

y = mx + b
m is the slope
b is the y-intercept

About Standard Form:

Ax + By = C
A & B & C are integers
A & B are both non-zero
This form is good to use when wanting to find the x & y intercepts of a line

About Point - Slope Form:

Y - Y1 = m (x -X1)
Y1 & X1 is a point on the line
The form allows you to identify the slope & the point on the line

Other Info:

Remember, y comes before the x
An ordered pair from your problem: (-3,1), -3 is x & 1 is y & x is before the y
An ordered pair from your problem: (3,5), 3 is x & 5 is y & x is before the y
For the graph, the vertical line is y

For the graph, the horizontal line is x

Hope this information helps!!! :)

5 0

2 years ago

arts and crafts shop has a bolt of crimson velvet 32 M long a customer came in during the morning and bought 120cm of the velvet

deff fn [24]

Answer:

2760

Step-by-step explanation:

I really don't know I just did 32x120

6 0

2 years ago

F(x)=-x^2-4x-6<br> Axis of symmetry and vertex

NikAS [45]

The vertex of the equation is ( -2 , -2 )

The axis of symmetry is x= - 2

5 0

2 years ago

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

romanna [79]

Answer:

11x+y = -28

Step-by-step explanation:

We have two points so we can find the slope

m = (y2-y2)/(x2-x1)

= (-6-5)/ (-2--3)

= -11(-2+3)

= -11/1

The slope is -11

We can use point slope to make an equation

y-y1 = m (x-x1)

y-5 = -11(x--3)

y -5 = -11(x+3)

Distribute

y-5 = -11x-33

Add 5 to each side

y-5+5 = -11x-33+5

y = -11x-28

Add 11x to each side

11x+y = -11x+11x-28

11x+y = -28

This is the standard form of a line

5 0

2 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

11 months ago