Answer:
To view the graph, go to desmos.com and start graphing, then type in: y/x=2/5 and the graph will appear
Step-by-step explanation:
The ratio 2:5, when represented in a graph, becomes y/x=2/5 and this means that if y is 2, then x is 5, and so on, and so forth.
Answer:
the answer is 3/4
Step-by-step explanation: 6/8 divided by 2 is 3/4
I am not that sure but I believe it would be 12 and 1/2 points since that would have brought him back up to 100%. Because if it was any other it would make his score lower than 100% or higher then 100%
Answer:
The bag contains fewer than 10 carrots.
Catherine biked farther than 10 miles.
The chair is shorter than 20 inches.
Carlos scored over 20 points.
Hope that helps you sorry if it doesn't.
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
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