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2 years ago

14

Suppose you went to a carnival.The price to get in was $4, and paid $0.50 to get on each ride. If you went to the carnival and r

ode 7 rrides, how much did you spend?
A.$11.50
B.$7.50
C.$9
D.$3.50

1 answer:

Novay_Z [31]2 years ago

7 0

B 7.50 reason total spent=4+.50(7)——-> 4+3.50———->$7.50

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She needs 3/4 cup of water she needs 10 more servings what's the answer A 1/1/5 b 3/1/4 c 7/2/4 d 8/2/3

Eddi Din [679]

<h2><u>Corect option</u> :</h2>

$= \color{plum}\tt(C) 7 \frac{2}{4}$

<h2><u>Answer with steps</u> :</h2>

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$= \tt \frac{3}{4} \: \times 10$

$= \tt\frac{30}{4}$

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Thus, she needs $\tt 7\frac{2}{4} \: cups$ of water.

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2 years ago

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3 years ago

Read 2 more answers

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3 years ago

(look at the images) can i get help on these?

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Answer:

see explanation

Step-by-step explanation:

15

JK + KL = JL , substitute values

2x + 1 + 6x = 81, that is

8x + 1 = 81 ( subtract 1 from both sides )

8x = 80 ( divide both sides by 8 )

x = 10

Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21

KL = 6x = 6 × 10 = 60

--------------------------------------------------------------

16

JK + KL = JL , substitute values

2x + x + 2 = 5x - 10 , that is

3x + 2 = 5x - 10 ( subtract 3x from both sides )

2 = 2x - 10 ( add 10 to both sides )

12 = 2x ( divide both sides by 2 )

6 = x

Thus

JK = 2X = 2 × 6 = 12

KL = x + 2 = 6 + 2 = 8

JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20

------------------------------------------------------------

17

Calculate the distance d using the distance formula

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with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)

d = $\sqrt{(1-7)^2+(-5-3)^2}$

= $\sqrt{(-6)^2+(-8)^2}$

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3 0

3 years ago