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MissTica
3 years ago
6

What are the 6 multiples of 2/5

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0
Some examples of multiples of 2/5 are 4/10, 6/15, 8/20, 10/25, 12/30, and 14/35.
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Please do this ASAP! Due tomorrow. 9:12pm here.
Mumz [18]

Answer:

compare (1/2)^3 is greater than (a/b)^2

Step-by-step explanation:

1/2*1/2*1/2= 0.125 or 1/8

1/4 * 1/4=0.0625 or 1/16

8 0
3 years ago
Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.
NemiM [27]

Complete question is;

Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.

1) 2x + y = 10

x - 3y = -2

2) x + 2y = 5

2x + y = 4

3) x + 3y = 5

6x - y = 11

4) 2x + y = 10

-6x - 3y = -2

Answer:

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Step-by-step explanation:

1) 2x + y = 10 - - - (eq 1)

x - 3y = -2 - - - (eq 2)

Multiply eq 1 by 3 to get;

6x + 3y = 30

Add it to eq 2 to get;

7x = 28

x = 28/7

x = 4

2) x + 2y = 5 - - - (eq 1)

2x + y = 4 - - - (eq 2)

Multiply eq 2 by 2 to get;

4x + 2y = 8

Subtract eq 1 from it to get;

3x = 3

x = 3/3

x = 1

3) x + 3y = 5 - - - (eq 1)

6x - y = 11 - - - (eq 2)

Multiply eq 2 by 3 to get;

18x - 3y = 33

Add to eq(1) to get;

19x = 38

x = 38/19

x = 2

4) 2x + y = 10 - - - (eq 1)

-6x - 3y = -2 - - - (eq 2)

Make y the subject in eq 1 to get;

y = 10 - 2x

Put in eq (2);

-6x - 3(10 - 2x) = -2

-6x - 30 + 6x = -2

0 = 0

Thus,no solution exists.

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

3 0
3 years ago
two students club plan to share a bus on a trip to the capital transportation at lunch for day cost $12 per student one club has
ozzi

Answer:

$516

Step-by-step explanation:

first you multiply 12 and 25 and you get 300

then you multiply 12 and 18 and you get 216

Then finally you add 216 and 300 together to get $516

7 0
3 years ago
PLS HELP ASAP PLZ PLZ PLZ
KIM [24]
I am unsure about the very last problem but I can help with the first two

1) (y+1)+4

If we combine the numbers 1 and 4, we get +5 and can isolate the numbers from the variable.

This would give us

y + 5 =

2) (6*r)*7

remember that we do not have to explicitly state 6*r

Instead, we can write it as 6r

this helps us get rid of the parentheses

now we can write it as 6r * 7=

I hope this helps!:)

6 0
3 years ago
What do you set each term equal to in order to solve for all of the "roots" of a function? No links please :)​
Citrus2011 [14]

Answer:

Solving quadratic equations can be difficult, but luckily there are several different methods that we can use depending on what type of quadratic that we are trying to solve. The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.

Step-by-step explanation:

can you mark me brainliest

3 0
3 years ago
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