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Oksanka [162]
3 years ago
14

What is an equation of the line that passes through the points (4,3) and (7,3)​

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

y = 3

Step-by-step explanation:

find out the slope

m = (3-3)/(4-7)

m = 0

so the line is horizontal

passing through the point (x,3)

x can be any value

so the equation is

y = 3

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A circle centered at (-2,3) and contains point (5,9) which represents the equation
SIZIF [17.4K]
The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
8 0
4 years ago
Find the area of the circle to the nearest whole number, if necessary!
astra-53 [7]

Answer:

The circle has an area of about 1385 square mm.

Step-by-step explanation:

Let's recall that circles have an area that can be found with the following formula:

A=\pi r^{2}

where r is the radius of the circle.

Now, focus your eyes on the circle. We are shown that the diameter of this circle is 42 mm, but we only want the radius. Since the radius is half the diameter, the radius is 21 mm. Now, we can solve for the area of the circle.

A=\pi (21)^2\\A=441\pi \\A=1385.44236...

So, to the nearest whole number, the area of the circle is 1385 square mm.

5 0
2 years ago
Which of the following accurately lists all discontinuities of the function below?
jeka94
Checking the <span>discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4
</span>
<span>Checking the <span>discontinuity at point -2
from the left f(-2) = </span></span><span><span>(-2+2)² = 0
</span>from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2
</span>
<span>Checking the <span>discontinuity at point 4
from the left f(4) = </span></span><span><span>-(1/2)*4+1 = -1
</span>from the right f(4) = -1
but there no equality in the equation so,
</span><span>∴ The function is discontinues at 4

The correct choice is the second
point </span>discontinuity at x = 4 and jump <span>discontinuity at x = -2</span>



5 0
3 years ago
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GEOMETRY HELP PLEASE!! WILL MARK BRAINLEIST!<br> 5
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AC=BD

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3 years ago
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Step-by-step explanation:

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