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Ray Of Light [21]
3 years ago
13

41 coins, consisting of nickels and quarters, have a total value of $4.65. How many coins of each kind are there?

Mathematics
1 answer:
aivan3 [116]3 years ago
5 0

You first have to make an simple equation.

x = How many pennies

y = How many quarters

After that, since a penny is 5 Cents and a quarter is 25 Cents, we make the equation as:

5x + 25y = 465 (cents)

To write the whole entire thing in an equation is:

x + y = 41

y = 41 - x    Since I brought the x from the left to right, we change the positive "x" to negative "y"

To bring the 'y = 41 - x' to 5x + 25y = 465, we get rid of the "y"s from both equations.

Now, you are left with the simplified equation:

5x+25(41-x)=465\\

25*41+5x-20x=465

-20x+25*41=465

-20x=465-(25*41)

-20x=465-1025

-20x=-560

20x=560

x=28

Now you find the y.

x = 28

28+y=41\\41-28=y\\y=13

Conclude:

So the y was the quarter and the x was the pennies.

Quarters = 13

Pennies = 28

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