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docker41 [41]
3 years ago
8

The sum of two consecutive multiples of 9 is 63 .Find these multiples​

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Step-by-step explanation:

divide 63 from 9

=the answer is 7

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209 divided by 3 estimate
SpyIntel [72]

Answer:

The quotient is estimated to be 69.

Other:

Brainliest? Thanks!

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2 years ago
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What is the y-value of the vertex of the function f(x)=−(x−3)(x+11)? −8 −4 33 49
alisha [4.7K]

Answer:

y - value of the vertex is 49.

Step-by-step explanation:

Given function is f(x) = -(x - 3)(x + 11)

f(x) = -(x² - 3x + 11x - 33)

     = -(x² + 8x - 33)

     = -(x² + 8x + 16 - 49)

     = -[(x + 4)² - 49]

     = -(x + 4)² + 49

Comparing this equation with the vertex form of a quadratic function,

f(x) = -(x - h)² + k

Where (h, k) is the vertex of the function.

Vertex of the parabola is (-4, 49)

Therefore, y-value of the vertex is 49.

4 0
2 years ago
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The cost of one can of soda if 6 cans cost n
Arturiano [62]

Answer

if 6 cans cost n

1 can would cost n/6

Example

6 cans cost 12

1 can would cost 12/6

which is 2

8 0
2 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
i need help with questions 12-15. you can choose one but if you can give me all the answers i will mark you brainliest
8090 [49]

For lines to be parallel, the slopes have to be the SAME.

For lines to be perpendicular, the slopes have to be the exact opposite. (opposite sign and number)

For example(perpendicular):

slope is 2

the perpendicular slope is -1/2

slope is -4/5

the perpendicular slope is 5/4


12. line a and b are perpendicular


13. Line a: y = 3/5x + 1

Line b: y = 3/5x - 2/5

Line c: y = 4/6 + 5/3x

line a and b are parallel


14. Line a: y = 3x + 6

Line b: y = 6 - 3x

Line c: y = 2/3x + 6

Neither, none of them are parallel or perpendicular


15. Line a: y = -2/3 + 4/3x

Line b: y = -1/4 - 3/4x

Line c: y = 5 + 3/4x

line a and b are perpendicular

6 0
3 years ago
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