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olga nikolaevna [1]
3 years ago
6

Number 11 plz help me

Mathematics
2 answers:
prisoha [69]3 years ago
8 0
No it did not because its going up forty percent of the new value
vovikov84 [41]3 years ago
5 0
I think its the same as it is the same up and down value. For example, if you add 5 to 0, you get 5 but then if you minus 5, it goes back to 0, your original number.
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Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
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Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
Help!! What is 78,400,000 expressed in scientific notation?
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2 years ago
Express 3/8 in thirty-seconds
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Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x+3) and (x+12)
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Answer:

A product of factors is zero if and only if one or more of the factors is zero.  That is, if ab = 0, then either a = 0 or b = 0 (or both).

Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both.  (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.

Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.

3 0
3 years ago
Read 2 more answers
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