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olga nikolaevna [1]
4 years ago
6

Number 11 plz help me

Mathematics
2 answers:
prisoha [69]4 years ago
8 0
No it did not because its going up forty percent of the new value
vovikov84 [41]4 years ago
5 0
I think its the same as it is the same up and down value. For example, if you add 5 to 0, you get 5 but then if you minus 5, it goes back to 0, your original number.
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Step-by-step explanation:

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kondor19780726 [428]

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A. Find value of x and KL if K is between J and L.
MrRa [10]

Answer:

x=3

Step-by-step explanation:

If k is between J and L, then

JK + KL = JL

2x+11 + (3x) = 13x-13

Combine like terms

5x +11 = 13x -13

Subtract 5x from each side

5x-5x+11 = 13x-5x-13

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3 years ago
The local amusement park was interested in the average wait time at their most popular roller coaster at the peak park time (2 p
Effectus [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

118, 124, 108, 116, 99, 125, 138, 118, 119, 121, 65, 130, 120

Ordered data:

65, 99, 108, 116, 118, 118, 119, 120, 121, 124, 125, 130, 138

1.)

90th percentile :

0.9(n + 1)th term

n = sample size = 13

0.9(14) th term

= 12.6th term

= (12 + 13)th / 2

= (130 + 138) / 2

= 134

Third quartile (Q3) = 75th percentile

0.75(n + 1)th term

n = sample size = 13

0.75(14) th term

= 10.5th term

= (10 + 11)th / 2

= (124 + 125) / 2

= 124.5

What is the first quartile?

First quartile (Q1) :

0.25(n + 1)th term

n = sample size = 13

0.25(14) th term

= 3.5th term

= (3 + 4)th / 2

= (108 + 116) / 2

= 112

(4) What is the 10th percentile?

0.1(n + 1)th term

n = sample size = 13

0.1(14) th term

= 1.4th term

= (1 + 2)th / 2

= (65 + 99) / 2

= 82

(5) 65tb percentile :

0.65(n + 1)th term

n = sample size = 13

0.65(14) th term

= 9.1th term

= (9 + 10)th / 2

= (121 + 124) / 2)

= 122.5

(6) What is the IQR?

Q3 - Q1

124.5 - 112

= 12.5

(7) What are the lower and upper limits?

Maximum = 138

Minimum = 65

4 0
3 years ago
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ss7ja [257]

Step-by-step explanation:

Subtract a from both sides

a-a+b-___=a-a

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Read 2 more answers
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