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2 years ago

6

Thank you will mark brainliest

1 answer:

frozen [14]2 years ago

8 0

Answer:

Option D

Step-by-step explanation:

We have to find the value of the composite function (h o k)(2).

Since, (h o k)(x) = h[k(x)]

(h o k)(2) = h[k(2)]

From the picture attached,

At x = 2

k(2) = (-2)

Therefore, h[k(2)] = h(-2)

Since, h(x) = $\frac{3}{x+1}$

Therefore, h(-2) = $\frac{3}{-2+1}$

= -3

(h o k)(2) = -3 is the answer.

Option (D) is the correct option.

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What is an equation of a parabola with a vertex at the origin and directrix x=4.75?

patriot [66]

An equation for the parabola would be y²=-19x.

Since we have x=4.75 for the directrix, this tells us that the parabola's axis of symmetry runs parallel to the x-axis. This means we will use the standard form

(y-k)²=4p(x-h), where (h, k) is the vertex, (h+p, k) is the focus and x=h-p is the directrix.

Beginning with the directrix:

x=h-p=4.75
h-p=4.75

Since the vertex is at (0, 0), this means h=0 and k=0:

0-p=4.75
-p=4.75
p=-4.75

Substituting this into the standard form as well as our values for h and k we have:
(y-0)²=4(-4.75)(x-0)
y²=-19x

4 0

3 years ago

PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

<em>(h, k)</em><em> - vertex</em>

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using $k+\dfrac{1}{4a}$

<em>k = -5</em>

$-5+\dfrac{1}{4a}=-4$ <em>add 5 to both sides</em>

$\dfrac{1}{4a}=1$ <em>multiply both sides by 4</em>

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

<em>use the distributive property: a(b+c)=ab+ac</em>

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

3 0

3 years ago

Daisy cut a square out of a sheet of graph paper. The square had an area of 16 square cm. She then trimmed 1 cm from each side o

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Answer: 4 cm^2, it went from 4x4 to 2x2.. clipped on all sides...

Hope I helped!

Giving me brainliest is much appreciated! :).

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3 years ago

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jeka94

Answer: I think it is greater than

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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