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Lynna [10]
3 years ago
12

Lines b and c are parallel.

Mathematics
2 answers:
bogdanovich [222]3 years ago
4 0

Answer:

B. m<2 = 50 degrees.

I just took the test.

fomenos3 years ago
3 0
Where is the diagram?
Can't be solved without it.
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Initial value problems dy/dx+2y=3. Y(0)=1
Pavel [41]

The initial value equation is y = \frac 12(3 - e^{-2x})

<h3>How to solve the initial value?</h3>

The equation is given as:

\frac{dy}{dx} +2y = 3

Where

Y(0) = 1

Subtract 2y from both sides in the equation

\frac{dy}{dx}  = -2y + 3

Rewrite as:

\frac{dy}{-2y + 3}  =  dx

Integrate both sides of the equation

-\frac 12\ln|-2y + 3| = x + C_o

Multiply through by -2

\ln|-2y + 3| = -2x + C_1

Take the exponent of both sides

-2y + 3 = Ce^{-2x

Next, we solve for C under the initial condition Y(0) = 1.

This gives

-2(1) + 3 = Ce^{-2 * 0

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in -2y + 3 = Ce^{-2x

-2y + 3 = e^{-2x

Next, we solve for y

y = \frac 12(3 - e^{-2x})

Hence, the initial value equation is y = \frac 12(3 - e^{-2x})

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2 years ago
Interpreting a Function
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A,C,D,E

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What is the slope and y-intercept of this equation?<br> y=2-9x<br> m=<br> b=
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Slope (m) is the number being multiplied by x (make sure you include the sign in front of it).

y- intercept (b) is the number other than the x

Step-by-step explanation:

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Answer:

<h3>r =-12</h3>

Step-by-step explanation:

2 + 1/3t = 1 + 1/4t\\\\2+\frac{1}{3}t=1+\frac{1}{4}t\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\2+\frac{1}{3}t-2=1+\frac{1}{4}t-2\\\\Simplify\\\frac{1}{3}t=\frac{1}{4}t-1\\\\\mathrm{Subtract\:}\frac{1}{4}t\mathrm{\:from\:both\:sides}\\\frac{1}{3}t-\frac{1}{4}t=\frac{1}{4}t-1-\frac{1}{4}t\\\\Simplify\\\frac{1}{12}t=-1\\\\\mathrm{Multiply\:both\:sides\:by\:}12\\12\times\frac{1}{12}t=12\left(-1\right)\\\\\\Simplify\\r =-12

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Choose the function whose graph is given by:
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Answer:

<h2>B. y= cos X</h2>

Step-by-step explanation:

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