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Dmitrij [34]
3 years ago
14

Please help ASAP!!!!!!!

Mathematics
2 answers:
JulsSmile [24]3 years ago
5 0

Answer:

  $86.81

Step-by-step explanation:

Using the given formula, we want to compute A for ...

  P = 4750

  r = 0.2279

  n = 365 . . . . . assuming "exact" interest

  t = 1 or 30

For 1 day late:

  A = 4750(1 +0.2279/365)^(365·(1/365)) = 4752.97

For 30 days late:

  A = 4750(1 +0.2279/365)^(365·(30/365)) = 4839.78

The difference in these payment amounts is ...

  $4839.78 -4752.97 = $86.81

You would save $86.81 in interest charges by paying only 1 day late.

_____

<em>Comment on the question</em>

It would be a poor choice of credit card to use one that compounds interest daily. Most do so on a monthly basis.

nalin [4]3 years ago
4 0
Answer 86.61 !


Explanation : copied other person if you don’t mind
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Sam is making a case for his calculator. It is a rectangular prism that will be 5.5 inches long by 2 inch wide by 5 inches high.
White raven [17]

Answer:

97in³

Step-by-step explanation:

L = 5.5, W = 2, H = 5

2(h × W) + 2(h × L) + 2(W × L)

= 2(5*2) + 2(5*5.5) + 2(2*5.5)

= 2(10) + 2(27.5) + 2(11)

= 20 + 55 + 22

= 97in³

8 0
3 years ago
1. Factor.......12x^5+6x^2−18
tester [92]
The answer is c.. Just use the distributive property on c and it will equal what you have to factor


5 0
3 years ago
Read 2 more answers
Evaluate f(x) = 2x +3 for f(4)<br> a-11<br> b-8<br> c-4<br> d-3
Scrat [10]

Answer:

the answer is a-11

Step-by-step explanation:

f(x)=2x+3

f(4)=2(4)+3

f(4)=8+3

f(4)=11

5 0
2 years ago
A. Write an equation that compares Tom sand Ann's ages.b. Draw a graph to represent theequation
kompoz [17]

a. The equation that relates Ann's age (x) and Tom's age (y) is a line

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept.

The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:

m=\frac{y_2-y_1}{x_2-x_1}

From the table, the line passes through the points (4, 8) and (8, 12), then its slope is:

m=\frac{12-8}{8-4}=\frac{4}{4}=1

Substituting with m = 1 and the point (4, 8) into the general equation, we get:

8 = 1(4) + b

8 = 4 + b

8 - 4 = b

4 = b

Finally, the equation that compares Tom's and Ann's age is:

y = x + 4

b. To graph the line y = x + 4, we need to draw two points and then connect them with a line. Replacing with x = 0 into the equation:

y = 0 + 4

y = 4

then, the point (0, 4) is on the line. And we can also use the point (4,8)

3 0
1 year ago
Any 10th grader solve it <br>for 50 points​
kkurt [141]

Answer:

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., a_{1}=A and common difference=D

The nth term can be written as

a_{n}=A+(n-1)D

pth term of given arithmetic progression is a

a_{p}=A+(p-1)D=a

qth term of given arithmetic progression is b

a_{q}=A+(q-1)D=b and

rth term of given arithmetic progression is c

a_{r}=A+(r-1)D=c

We have to prove that

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0

Now to prove LHS=RHS

Now take LHS

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)

=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)

=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)

=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}

=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}

=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

\neq 0

ie., RHS\neq 0

Therefore LHS\neq RHS

ie.,\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  

Hence proved

5 0
3 years ago
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