Firstly,
thanks for posting this.
81 = 9x9 or 9 squared so at this stage I'm guessing the last two.
x^ 8 = (x^ 4) x (x^ 2) (its called the multiplication rule of indices).
Okay I have approx 14 mins to answer.
No panic
√ 81.x^8 x <span>√ y^5
</span>√ (9x^2 x 9x^6) x <span>√ y^5
</span>= 9x x <span>√ 9x^6 x </span><span>√ y^5
</span>did I just gain time?
√ 9x^6 = <span>√ </span>3x ^3 x <span>√ 3x ^ 3
</span>or 2 . √ 3x^3. <span>√ y^5
</span>more time
okay, so that wasnt successful.
√ 9x^6 =<span>√ </span> (3x^2) x <span>√ </span>(3x^4)
Answer:
6%
Step-by-step explanation:
I asked this same exact question, no one got the right answer, so I just guessed, and what do you know, I got the answer right! So here you go.
Y=Mx +c
M gradient so count how many squares per one line
C = y intercept (7.5) here it looks
Just sub in those
9514 1404 393
Answer:
(a) 15/17
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the cosine relation:
Cos = Adjacent/Hypotenuse
cos(P) = PQ/PR
cos(P) = 15/17
Answer:
50
Step-by-step explanation:
42/n³∑k²+12/n²∑k+30/n∑1
=42/n³[n(n+1)(2n+1)/6]+12/n²[n(n+1)/2]+30/n [n]
=7n(n+1)(2n+1)/n³+6n(n+1)/n²+30
=7(n+1)(2n+1)/n²+6(n+1)/n+30
=[7(2n²+3n+1)+6(n²+n)+30n²]/n²
=[14n²+21n+7+6n²+6n+30n²]/n²
=[50n²+27n+7]/n²
=[50+27/n+7/n²]
→50 as n→∞
because 1/n,1/n²→0 as n→∞
