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WITCHER [35]
3 years ago
11

Find the missing angle measure for the quadrilaterals below.

Mathematics
2 answers:
Anna35 [415]3 years ago
7 0

Answer:

I haven't done this type of math in a while so sorry if it is wrong. The answer is 99

Step-by-step explanation:

All the angles will equal up to 360 degrees.

So add all of the angles and that will give you 261. Next, minus 360 and 261. That will give you 99.

Step 1: 108+72+81=261

Step 2: 360-261=99

(sorry if im wrong).

nydimaria [60]3 years ago
5 0

Answer:

1. = 99 degrees   2. = 85 degrees

Step-by-step explanation: All quadrilaterals have a total of 360 degrees. You can figure out the rest.

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Generate the nest three terms of each arithmetic sequence shown below.
o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

a_{n}=a_{1}+(n-1)d

Now

a_{2}=a_{1}+(2-1)d

a_{2}=a_{1}+(1)d

Substituting the given value we get

a_{2}= -2+(1)4

a_{2}= -2+4

a_{2}= 2

------------------------------------------

Similarly

a_{3}=a_{1}+(3-1)d

a_{3}=a_{1}+(2)d

Substituting the given value we get

a_{3}= -2+(2)4

a_{3}= -2+8

a_{3}= 6

-------------------------------------------------

a_{4}=a_{1}+(4-1)d

a_{4}=a_{1}+(3)d

Substituting the given value we get

a_{4}= -2+(3)4

a_{4}= -2+16

a_{4}= 10

-------------------------------------------------------------------------------------------

<u>B</u><u>  a_n=a_{(n-1)}-8  with a_1=10</u>

a_2=a_{(2-1)}-8

a_2=a_{1}-8

Substituting the given value

a_2= 10-8

a_2=2

---------------------------------------------------------------------

a_3=a_{(3-1)}-8

a_3=a_{2}-8

Substituting the  value

a_3=2-8

a_3= -6

---------------------------------------------------------------------

a_4=a_{(4-1)}-8

a_4=a_{3}-8

Substituting the  value

a_4= -6-8

a_4= -14

-------------------------------------------------------------------------------------------

<u>C) a_1=3, a_2=1</u>

Here the difference is -2

the arithmetic sequence formula is

a_{n}=a_{1}+(n-1)d

Now

a_{3}=a_{1}+(3-1)d

a_{3}=a_{1}+(2)d

Substituting the value we get

a_{3}= 3+(2)-2

a_{3}= 3-4

a_{3}= -1

------------------------------------------------------------------------------

a_{4}=a_{1}+(4-1)d

a_{4}=a_{1}+(3)d

Substituting the value we get

a_{4}= 3+(3)-2

a_{4}= 3-6

a_{4}= -3

----------------------------------------------------------------------------------

a_{5}=a_{1}+(5-1)d

a_{5}=a_{1}+(4)d

Substituting the value we get

a_{5}= 3+(4)-2

a_{5}= 3-8

a_{5}= -5

4 0
3 years ago
Consider this system of equations:
alexandr1967 [171]
<span>"For which value of k does the system have no real number solutions?"
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<span>
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<span>"For which value of k does the system have two real number solutions?"
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valina [46]

Answer:

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Step-by-step explanation:

an=a1+(n−1)d

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