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Maslowich
1 year ago
14

Kim purchased a dress that was originally $35. It was on sale for 30% off. She also bought a pair of shoes for 1/2 off the origi

nal price of $17. If the store added a 4% sales tax, how much would she pay for both items?
Mathematics
1 answer:
LUCKY_DIMON [66]1 year ago
5 0

Answer:  $34.32

Step-by-step explanation: We first calculate the price of the dress that was on sale. 30% of 35 is 35/10 x3. This is equal to 3.5x3 which is 7+3.5 = 10.5 We subtract this from 35 to get $24.5. So, the dress cost $24.5. Next 1/2 of 17 is 8.5. In total, the items cost $24.5+$8.5 = $33. Then, there is a 4% sales tax we have to add on to 33. 1% of 33 is 33/100 which is 0.33. This time 4 is 1.32. 33+1.32 is 34.32.

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The sale price of an item is $160 after a 20% off discount. What was the original price of the item?
bulgar [2K]

Answer:

200

Step-by-step explanation:

160/80 is 2. 2 times 100 is 200

6 0
3 years ago
If 3(d+1)=4(d–2)<br> then what is the value of 5(d–2)
Sonja [21]

Answer:

5(d - 2) = 45

Step-by-step explanation:

Solve the given equation for d

3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides

3d + 3 = 4d - 8 ( subtract 3d from both sides )

3 = d - 8 ( add 8 to both sides )

11 = d

Then

5(d - 2) = 5(11 - 2) = 5(9) = 45

3 0
2 years ago
Identify whether the problem is a percent increase or a percent decrease. Your $1000 investment earned 5% interest.
wolverine [178]

Answer:

Precent Increase

Step-by-step explanation:

8 0
3 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng
tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, xy \leq 8000

So,x(220-x) \leq 8000

220x-x^2 \leq 8000

So,220x-x^2 = 8000\\-x^2+220x-8000=0

General quadratic equation : ax^2+bx+c=0

Formula : x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0
3 years ago
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