Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
lol
A is true
B is true
C is false
D is false
E is false
You cant add a negative number.
If you add a negative number you will not have a full answer.
If there is 1 at the top, then you have 1, then 2, then 3, etc.
total number of oranges equals:
1 + 2 + 3 + ... + 16 + 17 + 18 <-- stop at 18 because this is the number of oranges at the base
You can use the formula:
sum of first n numbers = n*(n + 1)/2
-->
18*19/2 = 9*19 = 171
or you can figure it out (basically derive the above formula):
you have:
1 + 18 = 19
2 + 17 = 19
3 + 16 = 19
...
How many pairs do you have? Well, it's just the number of numbers: 1-18 = 18 numbers (divide by 2) = 9 pairs)
9 pairs of 19 = 9 * 19 = 171
Hope this helps!
Answer: 33+2, 32+3, 31+4, 30+5, 29+6, 28+7, 27+8, 26+9, 25+10, 24+11, 23+12, 22+13, 21+14, 20+15, 19+16, 18+17, 17+18, 16+19, 15+20, 14+21, 13+22, 12+23, 11+24, 10+25, 9+26, 8+27, 7+28, 6+29, 5+30, 4+31, 3+32, 1+34.
Step-by-step explanation: Plz give e brainliest