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lianna [129]
2 years ago
6

2. y - 8 = 15 y -0 =

Mathematics
1 answer:
Wewaii [24]2 years ago
6 0

Answer:

23

Step-by-step explanation:

I'm going to start by solving the first equation like so,

y - 8 = 15        (Remember what we do to one side we MUST do to the other)

<u>  +8    +8 </u>

y = 23

So know we know y = 23  What we have to do now is replace 23 for y in the second equation.

y - 0 = ?

23 - 0 = 23  

Hope that helps and have a great day!

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3 years ago
Enter the value of P so that the expression 4(10+n) is equivalent to 4(n+p)
Paraphin [41]

Answer:

I think it is 10

Step-by-step explanation:

Only because I believe n is still unknown and 4 must be multiplied

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frez [133]

SOLUTION:

Step 1:

From the given question, and comparing the scores in classes A and B

Step 2:

Question one, to know the class which had the better overall result on the exam;

(I) The scores in class A ranges from 65 to 100, while that of class B ranges from 60 to 90. This explains that class A had better results.

(ii) The median of the scores in class A is 85, while the median of the scores in class B is 75, this is another piece of supporting evidence that class A had better results.

Step 3:

Question two, to know the class which had greater variability in the results;

For a better understanding of this question, I need to explain the concept of variability in statistics.

Variability in statistics refers to the difference being exhibited by data points within a data set, as related to each other or as related to the mean. This can be expressed through the range, variance or standard deviation of a data set.

Step 4:

So we need to find the range of scores in each of the two classes and then compare, the class with the greater range has the greater variability.

The Range is the difference between the lowest and highest score (H - L), where H is the highest score and L is the lowest score.

Step 5:

Applying the formula for range stated in step 4;

For Class A; H = 100 and L = 65

For Class B; H = 90 and L = 60

The range for class A; H - L = 100 - 65 = 35

The range for class B; H - L = 90 - 60 = 30

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CONCLUSION:

Class A had better overall results in the exam and greater variability in the results.

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